Single phase non-ideal transformer. Turn Ratio= 3000/600. R₁ = 0.9Q R₂= 36 mQ Ro= 3000 Q X₁₁ = 0.6Q X12= 0.0024 Q X0= 6000 Q Input voltage-1440 V (also known as rms voltage) Load impedance of secondary winding is z₂= 0.12 + j0.3 Q a) Secondary winding current phasor 12 (NOT to be confused for I'₂) b) Load voltage phasor V2 (NOT to be confused for V'2) c) Primary winding current phasor ī₁ → X11 X12 R₁ R'2 www V₂ V₁ ī₁ R m ×°

Power System Analysis and Design (MindTap Course List)
6th Edition
ISBN:9781305632134
Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Chapter3: Power Transformers
Section: Chapter Questions
Problem 3.10P: A single-phase step-down transformer is rated 13MVA,66kV/11.5kV. With the 11.5 kV winding...
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Single phase non-ideal transformer. Turn Ratio= 3000/600.
R₁ = 0.9Q
R₂= 36 mQ
Ro= 3000 Q
X₁₁ = 0.6Q
X12= 0.0024 Q
X0= 6000 Q
Input voltage-1440 V (also known as rms voltage)
Load impedance of secondary winding is z₂= 0.12 + j0.3 Q
a) Secondary winding current phasor 12 (NOT to be confused for I'₂)
b) Load voltage phasor V2 (NOT to be confused for V'2)
c) Primary winding current phasor ī₁
→
X11
X12
R₁
R'2
www
V₂
V₁
ī₁
R
m
×°
Transcribed Image Text:Single phase non-ideal transformer. Turn Ratio= 3000/600. R₁ = 0.9Q R₂= 36 mQ Ro= 3000 Q X₁₁ = 0.6Q X12= 0.0024 Q X0= 6000 Q Input voltage-1440 V (also known as rms voltage) Load impedance of secondary winding is z₂= 0.12 + j0.3 Q a) Secondary winding current phasor 12 (NOT to be confused for I'₂) b) Load voltage phasor V2 (NOT to be confused for V'2) c) Primary winding current phasor ī₁ → X11 X12 R₁ R'2 www V₂ V₁ ī₁ R m ×°
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