of Procedure: "as given" Data Table: Molarity in bag 0 (H₂0) 0.2 M Sucrose 0.4 M Sucrose 0.6 M Sucrose 0.8 M Sucrose initial mass (g) Unknown JO 1.0 M Sucrose DD O 10 CO 10 final mass (g) 10.3 11.2 14.8 16.5 17.2 12.8 (final mass-initial mass) X 100 initial mass % change my group % change class average 4 Tre the workspace in the data table for help. 020 78 ia) Include a
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- Table 1 - Comparison of the effect of catechol concentration on the amount of product formed. Absorbance Potato extract Absorbance 0 mins after 30mins (2nd reading) (mL) 1st reading 1 Tube # la blank 2a 3a 4a 1 1 1 dH₂O Catechol (mL) (mL) 7 5 3 1 0 2 4 6 0.00 0.060 0.033 0-05-2 Q4) Give 2 reasons for adding dH₂O to these tubes in Table 1? Time for reading: 3:21 -0.11 Absorbance: Time for reading: 3.36 Q5) Tube la serves as a control, but why is this control needed? Absorbance: 0.197 Time for reading: 3.37 Based on the data from Table 1 answer these questions: Q1) What is the name of the enzyme found in potato extract? Answer: catechol Q2) What is the substrate? Answer: THO Q3) Name of product of this enzyme catalyzed reaction? Answer: Absorbance: 0.152 Time for reading: 3:39 Absorbance: . 166 ness Catechol Benzoquinone Subtract 1st from 2nd reading -0.01 0-137 0.11.19 0.119 Q6) Notice that your 1st absorbance reading in tubes 2a-4a are quite similar but it then becomes very different…Convert the experimental glucose concentration from mM (millimolar) to g/100 mL. 1/100 Dilution factor, Assume 1L of Solution. Show ALL Steps 2.340 mMCompute for the lactic acid content of these samples given the values below. Show your solution Volume of 0.1 N NaOH in 1st Sampling: 10 mL Volume of 0.1 N NaOH in 2nd Sampling: 40 mL Volume of sample used: 10ml
- Downloads/OCR ExamBulder e 4um Fig. 17.2 i) The diameter of the Kupffer cell in the image is 9.1 cm. Assuming it is spherical, caloulate the actual volume of this cell. Give your answer to four significant figures Show your working GOODData for standard glucose concentrations Glucose concentration (mm) 0 0.5 1 1.5 -~~ 2 2.5 A Data for plasma samples B Patient Timepoint (hours) C D E 0 0.5 1 2 0 0.5 1 2 0 0.5 1 2 1. Draw a standard curve of absorbance at 420nm against glucose concentration in mmoles/L. We recommend you use Excel or a similar programme to insert the graph Alternatively, you can draw by hand on graph paper and insert a photo of the graph. OON 0 0.5 1 Absorbance 1 0.000 0.477 0.947 1.234 1.733 2.160 2 0 0.5 1 Absorbance Absorbance 2 0.000 0.482 0.941 1.236 1.721 2.276 Absorbance Glucose concentration Glucose concentration Abs 1 Abs 2 Average from graph (mM) in plasma (mm) 0.635 0.632 0.629 1.368 1.370 1.369 1.382 1.388 1.385 1.151 1.147 1.149 0.566 0.844 0.869 0.772 0.395 0.397 0.399 0.850 0.858 0.854 0.738 0.744 0.741 0.539 0.531 0.535 0.776 0.780 0.778 1.475 1.481 1.478 1.446 1.444 1.445 1.302 1.296 1.299 0.560 0.563 0.848 0.846 0.871 0.870 0.774 0.773 Average 0.000 0.480 0.944 1.235 1.727 2.218 0.440…Table 1 Rate of pressure change (kPa/min) Sucrose solution concentration (M) 3078 0,1460 0.009095 1.0 0.9 0.8 0.7 -0.02370O
- Please answer these question. I need these for lab. PRE-LAB ASSIGNMENT – (YOU WILL NOT BE ALLOWED TO BEGIN WORK ON LABWITHOUT THE COMPLETED CALCULATIONS) 1. COMPLETE ALL CALCULATIONS REQUIRED FOR TABLE 1 ( For all measurements, the [PNPP] concentration will be 600 μM in a 1 ml final volume.) PNPP (substrate) stock solution: 100 mM PNPP in buffer 2. IN YOUR LAB NOTEBOOK, DRAW YOUR PREDICTION OF WHAT THEFOLLOWING GRAPHS MIGHT LOOK LIKEa. pH vs. V0b. TEMP vs. V03. OUTLINE THE BEST/MOST EFFICIENT WAY TO PREPAREDesired Desired Initial Volume of Stock or Volume of Concentration Volume Concentration Previous Dilution Distilled Water (C2) (V2) (C1) (V1), µL (V2- V1), µL 100 mg/dL 1.2 mL 200 mg/dL 75 mg/dL 1.2 mL 100 mg/dL* 50 mg/dL 1.2 mL 25 mg/dL 1.2 mLCalculate the amount of protein (in mg) in Sample 1 if the measurement at A280 = 0.197, taking into account the dilution factor 100 per and total volume of extract 140ml
- C. The following successive dilutions are applied to a stock solution that is 5.60 M sucrose: Solution A = 46.0 mL of the stock solution is diluted to 116 mL %3D Solution B = 58.0 mL of Solution A is diluted to 248 mL Solution C = 87.0 mL of Solution B is diluted to 287 mL 1. What is the concentration of sucrose in solution B? 2. What is the concentration of sucrose in solution C? 3. What is the dilution factor of Solution A? 4. What is the dilution factor of Solution B? 5. What is the dilution factor of Solution C?46 50 52 60 41 46 55 Find the ff. WITH SOLUTION PLEASE MeanMedianModeSDVarianceCVQuartile 2Decile 7Percentile 25Percentile 30I am not sure how to go about illustrating and answering this question: Use a diagram to illustrate how 10^-4, 10^-6 and 10^-8 dilutions in water of the soil suspension in a final volume of 10 mL will be prepared. There are only three tubes available.