16.17N2(8) + 3F2(g) → 2NF3(g)ΔΗAS° = -278 J/KN2(g) + 3C12(g) → 2NC13(g)N2F1(8) → 2NF2(g)ΔΗ85 kJAs° = 198 J/K-249 kJAH° = 460 kJAS° = -275 J/KSpontaneous at allNonspontaneous at allSpontaneous at lowtemperatures andnonspontaneous at hightemperaturesSpontaneous at hightemperatures andnonspontaneous at lowtemperaturestemperaturestemperaturesB. At what temperature (if any) would the decomposition of POCI3 become spontaneous?Express the temperature in kelvins to three significant digits. If there is no answer, enter none.

Since you have posted question with multiple subparts as per guidelines we can answer only three per…

N2(8) + 3F2(g) → 2NF3(g) N2(g) + 3C12(g) → 2NC13(g) AH° = 460 kJ AS® = -275 J/K N2F4(g) → 2NF2(g) AH° = 85 kJ As° = 198 J/K AH° = -249 kJ As° = -278 J/K Spontaneous at low temperatures and nonspontaneous at high temperatures ontaneous at all Nonspontaneous at all temperatures Spontaneous a temperatures nonspontaneous temperature emperatures

N2(8) + 3F2(g) → 2NF3(g) N2(g) + 3C12(g) → 2NC13(g) AH° = 460 kJ AS® = -275 J/K N2F4(g) → 2NF2(g) AH° = 85 kJ As° = 198 J/K AH° = -249 kJ As° = -278 J/K Spontaneous at low temperatures and nonspontaneous at high temperatures ontaneous at all Nonspontaneous at all temperatures Spontaneous a temperatures nonspontaneous temperature emperatures

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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