Example: At 25°C, calculate the AG° N₂+ 3H2 → 2NH3 • AG° N2(g) = 0 kJ/mol f • AG + H2(g) = 0 kJ/mol f • AG˚ NH 3(g) = -16.66 kJ/mol f a) 12.9 kJ b) -33.3 kJ c) -16.7 kJ d) -8.33 kJ e) Unsure sys for: AG sys =ΣnpG˚ products - Σn,G° reactants 60
Example: At 25°C, calculate the AG° N₂+ 3H2 → 2NH3 • AG° N2(g) = 0 kJ/mol f • AG + H2(g) = 0 kJ/mol f • AG˚ NH 3(g) = -16.66 kJ/mol f a) 12.9 kJ b) -33.3 kJ c) -16.7 kJ d) -8.33 kJ e) Unsure sys for: AG sys =ΣnpG˚ products - Σn,G° reactants 60
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
Related questions
Question
![Example: At 25°C, calculate the AG°
N₂+ 3H2 → 2NH3
• AG° N2(g) = 0 kJ/mol
f
• AG + H2(g) = 0 kJ/mol
f
• AG˚ NH 3(g) = -16.66 kJ/mol
f
a) 12.9 kJ
b) -33.3 kJ
c) -16.7 kJ
d) -8.33 kJ
e) Unsure
sys
for:
AG sys =ΣnpG˚ products - Σn,G° reactants
60](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F323fe199-1855-4807-b05f-f908edd7e1e9%2Fc75cb9bd-09b5-4c9f-a45f-d320f52b2afb%2F7evahh_processed.png&w=3840&q=75)
Transcribed Image Text:Example: At 25°C, calculate the AG°
N₂+ 3H2 → 2NH3
• AG° N2(g) = 0 kJ/mol
f
• AG + H2(g) = 0 kJ/mol
f
• AG˚ NH 3(g) = -16.66 kJ/mol
f
a) 12.9 kJ
b) -33.3 kJ
c) -16.7 kJ
d) -8.33 kJ
e) Unsure
sys
for:
AG sys =ΣnpG˚ products - Σn,G° reactants
60
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