Consider the reaction: СаСОз{(s) —СаО(9) + СO2(g) Using standard thermodynamic data at 298K, calculate the free energy change when 2.20 moles of CaCO3(s) react at standard conditions. AG°, kJ rxn
Calcium | ΔHof (kJ/mol) | ΔGof (kJ/mol) | So (J/mol K) |
---|---|---|---|
Ca (s) |
0 |
0 |
41.4 |
Ca (g) |
178.2 |
144.3 |
158.9 |
Ca2+ (g) |
1925.9 |
||
CaC2 (s) |
-59.8 |
-64.9 |
70.0 |
CaCO3 (s, calcite) |
-1206.9 |
-1128.8 |
92.9 |
CaCl2 (s) |
-795.8 |
-748.1 |
104.6 |
CaF2 (s) |
-1219.6 |
-1167.3 |
68.9 |
CaH2 (s) |
-186.2 |
-147.2 |
42.0 |
CaO (s) |
-635.1 |
-604.0 |
39.8 |
CaS (s) |
-482.4 |
-477.4 |
56.5 |
Ca(OH)2 (s) |
-986.1 |
-898.5 |
83.4 |
Ca(OH)2 (aq) |
-1002.8 |
-868.1 |
-74.5 |
Ca3(PO4)2 (s) |
-4126.0 |
-3890.0 |
241.0 |
CaSO4 (s) |
-1434.1 |
-1321.8 |
106.7 |
CaSiO3 (s) |
-1630.0 |
-1550.0 |
84.0 |
Carbon | ΔHof (kJ/mol) | ΔGof (kJ/mol) | So (J/mol K) |
---|---|---|---|
C (s, graphite) |
0 |
0 |
5.7 |
C (s, diamond) |
1.9 |
2.9 |
2.4 |
C (g) |
716.7 |
671.3 |
158.1 |
CCl4 (l) |
-135.4 |
-65.2 |
216.4 |
CCl4 (g) |
-102.9 |
-60.6 |
309.9 |
CHCl3 (l) |
-134.5 |
-73.7 |
201.7 |
CHCl3 (g) |
-103.1 |
-70.3 |
295.7 |
CH4 (g) |
-74.8 |
-50.7 |
186.3 |
CH3OH (g) |
-200.7 |
-162.0 |
239.8 |
CH3OH (l) |
-238.7 |
-166.3 |
126.8 |
H2CO (g) |
-116.0 |
-110.0 |
219.0 |
HCOOH (g) |
-363.0 |
-351.0 |
249.0 |
HCN (g) |
135.1 |
125.0 |
202.0 |
C2H2 (g) |
226.7 |
209.2 |
200.9 |
C2H4 (g) |
52.3 |
68.2 |
219.6 |
CH3CHO (g, acetaldehyde) |
-166.0 |
-129.0 |
250.0 |
C2H4O (g, ethylene oxide) |
-53.0 |
-13.0 |
242.0 |
CH3CH2OH (l) |
-277.7 |
-174.8 |
160.7 |
CH3CH2OH (g) |
-235.1 |
-168.5 |
282.7 |
CH3COOH (l) |
-484.0 |
-389.0 |
160.0 |
C2H6 (g) |
-84.7 |
-32.8 |
229.6 |
C3H6 (g) |
20.9 |
62.7 |
266.9 |
C3H8 (g) |
-103.8 |
-23.5 |
269.9 |
CH2=CHCN (l) |
152.0 |
190.0 |
274.0 |
C6H6 (l) |
49.0 |
124.5 |
172.8 |
C6H12O6 (s) |
-1275.0 |
-911.0 |
212.0 |
CO (g) |
-110.5 |
-137.2 |
197.7 |
CO2 (g) |
-393.5 |
-394.4 |
213.7 |
CS2 (g) |
117.4 |
67.1 |
237.8 |
COCl2 (g) |
-218.8 |
-204.6 |
283.5 |
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