Given the following at 25 °C and 1.00 atm: 2Fe(s) + 02(g) → 2FeO(s) 4Fe(s) + 302(g) → 2FE203(s) AH° = -1648.8 kJ AH° = -544.0 kJ %3D 3Fe(s) + 202(g) → Fe304(s) AH° = -1118.4 kJ Calculate the AH for the reaction below at 25 °C. Fe203(s) + FeO(s) → Fe304(s) a. 249.8 kJ O b.22.2 kJ O c. 1074.0 kJ d.-1074.0 kJ e. -22.0 kJ

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Chapter1: Chemical Foundations
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Given the following at 25 °C and 1.00 atm:
2Fe(s) + 02(g) → 2FeO(s)
4Fe(s) + 302(g) → 2FE203(s) AH° = -1648.8 kJ
AH° = -544.0 kJ
%3D
3Fe(s) + 202(g) → Fe304(s)
AH° = -1118.4 kJ
Calculate the AH for the reaction below at 25 °C.
Fe203(s) + FeO(s) → Fe304(s)
a. 249.8 kJ
O b.22.2 kJ
O c. 1074.0 kJ
d.-1074.0 kJ
e. -22.0 kJ
Transcribed Image Text:Given the following at 25 °C and 1.00 atm: 2Fe(s) + 02(g) → 2FeO(s) 4Fe(s) + 302(g) → 2FE203(s) AH° = -1648.8 kJ AH° = -544.0 kJ %3D 3Fe(s) + 202(g) → Fe304(s) AH° = -1118.4 kJ Calculate the AH for the reaction below at 25 °C. Fe203(s) + FeO(s) → Fe304(s) a. 249.8 kJ O b.22.2 kJ O c. 1074.0 kJ d.-1074.0 kJ e. -22.0 kJ
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