Consider the problem below: (Equation 1) 2 Ca(s) + O2(g) ---> 2 CaO(s) AH = -1270.2 kJ (Equation 2) 4 Zn(s) + 2 02(g) --> 4 ZnO(s) AH = -696.6 kJ %3D (Equation 3) 4 Ca(s) + 4 ZnO(s) ---> 4 Zn(s) + 4 CaO(s) AH = The AH for equation 3 is: (express in kJ)

Chemistry
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Chapter1: Chemical Foundations
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### Consider the Problem Below:

**Equation 1:**

\[2 \text{Ca}_{(s)} + \text{O}_2{(g)} \rightarrow 2 \text{CaO}_{(s)} \quad \Delta H = -1270.2 \, \text{kJ}\]

**Equation 2:**

\[4 \text{Zn}_{(s)} + 2 \text{O}_2{(g)} \rightarrow 4 \text{ZnO}_{(s)} \quad \Delta H = -696.6 \, \text{kJ}\]

**Equation 3:**

\[4 \text{Ca}_{(s)} + 4 \text{ZnO}_{(s)} \rightarrow 4 \text{Zn}_{(s)} + 4 \text{CaO}_{(s)} \quad \Delta H = ???\]

The \(\Delta H\) for equation 3 is: ______ (express in kJ)

### Screen Reader Version:

Consider the problem below:

*Equation 1:*

2 "C" a subscript (s) plus O subscript 2 subscript (g) arrow 2 "C" a O subscript (s) \(\Delta H =\) minus 1270.2 kJ

*Equation 2:*

4 Z n subscript (s) plus 2 O subscript 2 subscript (g) arrow 4 Z n O subscript (s) \(\Delta H =\) minus 696.6 kJ

*Equation 3:*

4 "C" a subscript (s) plus 4 Z n O subscript (s) arrow 4 Z n subscript (s) plus 4 "C" a O subscript (s) \(\Delta H = ???\)

The \(\Delta H\) for equation 3 is: ______ (express in kJ)
Transcribed Image Text:### Consider the Problem Below: **Equation 1:** \[2 \text{Ca}_{(s)} + \text{O}_2{(g)} \rightarrow 2 \text{CaO}_{(s)} \quad \Delta H = -1270.2 \, \text{kJ}\] **Equation 2:** \[4 \text{Zn}_{(s)} + 2 \text{O}_2{(g)} \rightarrow 4 \text{ZnO}_{(s)} \quad \Delta H = -696.6 \, \text{kJ}\] **Equation 3:** \[4 \text{Ca}_{(s)} + 4 \text{ZnO}_{(s)} \rightarrow 4 \text{Zn}_{(s)} + 4 \text{CaO}_{(s)} \quad \Delta H = ???\] The \(\Delta H\) for equation 3 is: ______ (express in kJ) ### Screen Reader Version: Consider the problem below: *Equation 1:* 2 "C" a subscript (s) plus O subscript 2 subscript (g) arrow 2 "C" a O subscript (s) \(\Delta H =\) minus 1270.2 kJ *Equation 2:* 4 Z n subscript (s) plus 2 O subscript 2 subscript (g) arrow 4 Z n O subscript (s) \(\Delta H =\) minus 696.6 kJ *Equation 3:* 4 "C" a subscript (s) plus 4 Z n O subscript (s) arrow 4 Z n subscript (s) plus 4 "C" a O subscript (s) \(\Delta H = ???\) The \(\Delta H\) for equation 3 is: ______ (express in kJ)
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