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29. Calculate the AH°xn using the following standard free energies of formation: SiCl4 (g) + 2 Mg (s) → 2 MgCl2(s) + Si(s) AH° (kJ/mol): - 616.98 0 -591.79 0 A) -566.60 kJ B)-25.19 kl C) 25.19 kl D) 566.60 kJ AH°rxn = ? . Use Hess's Law to find AG rxn for: CIO (g) + 03 (g) → Cl (g) + 202 (g) AG = ? Given the following: 203 (g) →3 02 (g) AG=+489.6 kl Cl (g) + 03 (g) → CIO (g) + O2 (g) AG = -34.5 kJ A) - 472.4 kJ B) - 210.3 kJ C) +455.1 kJ D) + 262.1 kJ E) +524.1 kJ

29. Calculate the AH°xn using the following standard free energies of formation: SiCl4 (g) + 2 Mg (s) → 2 MgCl2(s) + Si(s) AH° (kJ/mol): - 616.98 0 -591.79 0 A) -566.60 kJ B)-25.19 kl C) 25.19 kl D) 566.60 kJ AH°rxn = ? . Use Hess's Law to find AG rxn for: CIO (g) + 03 (g) → Cl (g) + 202 (g) AG = ? Given the following: 203 (g) →3 02 (g) AG=+489.6 kl Cl (g) + 03 (g) → CIO (g) + O2 (g) AG = -34.5 kJ A) - 472.4 kJ B) - 210.3 kJ C) +455.1 kJ D) + 262.1 kJ E) +524.1 kJ

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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29. Calculate the AH°xn using the following standard free energies of formation: SiCl4 (g) + 2 Mg (s) → 2 MgCl2(s) + Si(s) AH° (kJ/mol): - 616.98 0 -591.79 0 A) -566.60 kJ B)-25.19 kl C) 25.19 kl D) 566.60 kJ AH°rxn = ?
Transcribed Image Text:29. Calculate the AH°xn using the following standard free energies of formation: SiCl4 (g) + 2 Mg (s) → 2 MgCl2(s) + Si(s) AH° (kJ/mol): - 616.98 0 -591.79 0 A) -566.60 kJ B)-25.19 kl C) 25.19 kl D) 566.60 kJ AH°rxn = ?
. Use Hess's Law to find AG rxn for: CIO (g) + 03 (g) → Cl (g) + 202 (g) AG = ? Given the following: 203 (g) →3 02 (g) AG=+489.6 kl Cl (g) + 03 (g) → CIO (g) + O2 (g) AG = -34.5 kJ A) - 472.4 kJ B) - 210.3 kJ C) +455.1 kJ D) + 262.1 kJ E) +524.1 kJ
Transcribed Image Text:. Use Hess's Law to find AG rxn for: CIO (g) + 03 (g) → Cl (g) + 202 (g) AG = ? Given the following: 203 (g) →3 02 (g) AG=+489.6 kl Cl (g) + 03 (g) → CIO (g) + O2 (g) AG = -34.5 kJ A) - 472.4 kJ B) - 210.3 kJ C) +455.1 kJ D) + 262.1 kJ E) +524.1 kJ
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