Use the following data to determine the ΔH° for the conversion of diamond into graphite:\[ \text{C(s, diamond)} + \text{O}_2(g) \rightarrow \text{CO}_2(g) \]\[ \Delta H° = -395.4 \, \text{kJ} \]\[ 2\text{CO}_2(g) \rightarrow 2\text{CO}(g) + \text{O}_2(g) \]\[ \Delta H° = 566.0 \, \text{kJ} \]\[ 2\text{CO}(g) \rightarrow \text{C(s, graphite)} + \text{CO}_2(g) \]\[ \Delta H° = -172.5 \, \text{kJ} \]\[ \text{C(s, diamond)} \rightarrow \text{C(s, graphite)} \]\[ \Delta H° = -1.13 \times 10^3 \, \text{kJ} \rightarrow \]

The enthalpy change is a state function and the Hess law states that the change of enthalpy in a chemical reaction is independent of the pathway between the initial and final states.According to this law, the total enthalpy change during a complete chemical reaction is the same whether the reaction is made in one step or in several steps. A chemical equation can be added, subtracted, multiplied, or divided similar to an algebraic equation. The reactions of known enthalpy are as follows: Cs,diamond + O2g → CO2g ∆Ho=-395.4 kJ2CO2g→ 2COg + O2g ∆Ho=566.0 kJ2COg→ Cs, graphite + CO2g ∆Ho=-172.5 kJLet's add the three equations written above: Cs,diamond + O2g → CO2g ∆Ho=-395.4 kJ2CO2g→ 2COg + O2g ∆Ho=566.0 kJ2COg → Cs, graphite + CO2g ∆Ho=-172.5 kJ-----------------------------------Cs,diamond → Cs, graphite ∆Ho=-395.4+556.0-172.5=-1.9 kJ-----------------------------------The enthalpy change of the given reaction is as follows: C(s,diamond) → C(s, graphite) ∆Ho=-1.9 kJ

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Chemistry

Use the following data to determine the AH° for the conversion of diamond into graphite: C(s,diamond) + O₂(g) co₂2(g) ΔΗ°= -395.4 kJ 2CO₂ (g) 200(g) + O₂(g) ΔΗ° = 566.0 kJ 2CO(g) →→→ C(s,graphite) + CO₂(g) ΔΗ°= -172.5 kJ C(s,diamond)→→→→→ C(s,graphite) AH°= -1.13 x 10 3 kJ +

Use the following data to determine the AH° for the conversion of diamond into graphite: C(s,diamond) + O₂(g) co₂2(g) ΔΗ°= -395.4 kJ 2CO₂ (g) 200(g) + O₂(g) ΔΗ° = 566.0 kJ 2CO(g) →→→ C(s,graphite) + CO₂(g) ΔΗ°= -172.5 kJ C(s,diamond)→→→→→ C(s,graphite) AH°= -1.13 x 10 3 kJ +

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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