Mutant naploid strain Mate T al a Diploid a (rows) Growth on minimal medium? No Yes Same complementation group Different complementation groups Mutant haploid strain a Experimental outline The eight a and eight & trp mutant strains are combined in all possible a/a pairs on a plate of rich medium according to the following grid. 1/1 1/2 13 14 15 16 17 1/8 212 213 214 215 216 217 218 HHH 3/3 3/4 3/5 3/6 3/7 3/8 678 a Master a (columns) The patches are allowed to grow overnight during which the haploids fuse into diploids. A very light inoculum of each patch is then transferred to an unsupplemented minimal plate in the same pattern as above, and the plate is incubated for two days at 30°C. Growth or absence of growth is then determined for each patch. 414 415 416 417 418 5/5 5/6 5/7 5/8 6/66/74/8 7/7718 1 345 6 7 8 a Master OCH Mating plate Rich medium Transfer 24 hr later Complementation plate Minimal medium Score results 48 hr later Question 11: If mutant haploid strain is mixed with a wild-type haploid strain, how many chromosomes will their progeny have?

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Experiment:
Saccharomyces cerevisiae can exist stably in either a haploid or a diploid state. A haploid S. cerevisiae
cell has 16 chromosomes. When certain haploids come into contact, they fuse their cell walls and
membranes, followed by the fusion of their nuclear membranes. The single nucleus now has 32
chromosomes, 16 from each parent strain, and is thus a diploid.
Haploid yeast strains divide mitotically to give rise to haploid progeny, and diploid strains divide
mitotically to give rise to diploid progeny. Certain haploids can fuse to form diploids. Haploid S.
cerevisiae exists in two "mating types," called a and a. Mating occurs only between a and a cells; no
mating occurs between cells of identical mating type.
We have a collection of eight a haploid mutant strains and eight a haploid mutant strains of yeast
unable to synthesize tryptophan (trp). These will be combined (mated) in all possible combinations
to yield diploid strains. If the diploids can grow on minimal medium, complementation occurred
between the genomes of the two haploids, and the mutations are thus in different complementation
groups. If the diploids fail to grow on minimal medium, then no complementation occurred and the
mutations lie within the same gene, or same complementation group.
Mutant haploid strain a
Mutant haploid strain a
Mate
a/a Diploid
Growth on minimal medium?
No
Yes
Same complementation group Different complementation groups
Experimental outline
The eight a and eight & trp mutant strains are combined in all possible a/a pairs on a plate of rich
medium according to the following grid.
a (columns)
1/1 1/2 1/3 1/4 1/5 1/6 1/7 1/8
2/2 213 214 215 216 217 218
3/3 3/4 3/5 3/6 3/7 3/8
4/4 4/5 4/6 4/7 4/8
a (rows)
5/5 5/6 5/7 5/8
6/6 6/7 6/8
7/7 7/8
8/8
The patches are allowed to grow overnight during which the haploids fuse into diploids. A very light
inoculum of each patch is then transferred to an unsupplemented minimal plate in the same pattern
as above, and the plate is incubated for two days at 30°C. Growth or absence of growth is then
determined for each patch.
678
1 2
345
6 7 8
a Master
HOPCH
a Master
Mating plate
Rich medium
Transfer
24 hr later
Complementation plate
Minimal medium
Score results 48 hr later
Question 11: If mutant haploid strain is mixed with a wild-type haploid strain, how many
chromosomes will their progeny have?
Transcribed Image Text:Experiment: Saccharomyces cerevisiae can exist stably in either a haploid or a diploid state. A haploid S. cerevisiae cell has 16 chromosomes. When certain haploids come into contact, they fuse their cell walls and membranes, followed by the fusion of their nuclear membranes. The single nucleus now has 32 chromosomes, 16 from each parent strain, and is thus a diploid. Haploid yeast strains divide mitotically to give rise to haploid progeny, and diploid strains divide mitotically to give rise to diploid progeny. Certain haploids can fuse to form diploids. Haploid S. cerevisiae exists in two "mating types," called a and a. Mating occurs only between a and a cells; no mating occurs between cells of identical mating type. We have a collection of eight a haploid mutant strains and eight a haploid mutant strains of yeast unable to synthesize tryptophan (trp). These will be combined (mated) in all possible combinations to yield diploid strains. If the diploids can grow on minimal medium, complementation occurred between the genomes of the two haploids, and the mutations are thus in different complementation groups. If the diploids fail to grow on minimal medium, then no complementation occurred and the mutations lie within the same gene, or same complementation group. Mutant haploid strain a Mutant haploid strain a Mate a/a Diploid Growth on minimal medium? No Yes Same complementation group Different complementation groups Experimental outline The eight a and eight & trp mutant strains are combined in all possible a/a pairs on a plate of rich medium according to the following grid. a (columns) 1/1 1/2 1/3 1/4 1/5 1/6 1/7 1/8 2/2 213 214 215 216 217 218 3/3 3/4 3/5 3/6 3/7 3/8 4/4 4/5 4/6 4/7 4/8 a (rows) 5/5 5/6 5/7 5/8 6/6 6/7 6/8 7/7 7/8 8/8 The patches are allowed to grow overnight during which the haploids fuse into diploids. A very light inoculum of each patch is then transferred to an unsupplemented minimal plate in the same pattern as above, and the plate is incubated for two days at 30°C. Growth or absence of growth is then determined for each patch. 678 1 2 345 6 7 8 a Master HOPCH a Master Mating plate Rich medium Transfer 24 hr later Complementation plate Minimal medium Score results 48 hr later Question 11: If mutant haploid strain is mixed with a wild-type haploid strain, how many chromosomes will their progeny have?
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