Table of ReactantsMolecular weight (g/mol)Literature MP ("C)Density (g/ml)Amount Used (g or mL)Amount Used (mol)Benzyltriphenyiphosphoniumchloride338.93371.180.764 g74.12-116.30.714Anhydrous diethyl ether4.00 mlBenzaldehyde106.1-261.040.200 gWhat is the limiting reactant?Choose.Molecular weight of stilbene producti Product theoretical yield (a)Recrystallized product percent yield

Amount used in moles is calculated using the equation Number of moles =Amount used (g)Molecular…

Molecular weight (g/mol) Literature MP ("C) Density (g/ml.) Amount Used (g or ml) Amount Used (mol) Benzyltriphenylphosphonium chloride 338.9 337 1.18 0.764 g Anhydrous diethyl ether 74.12 -116.3 0.714 4.00 ml Benzaldehyde 106.1 26 1.04 0 200 g 'what is the limiting reactant? Choose. Molecular weight of stilbene product

Molecular weight (g/mol) Literature MP ("C) Density (g/ml.) Amount Used (g or ml) Amount Used (mol) Benzyltriphenylphosphonium chloride 338.9 337 1.18 0.764 g Anhydrous diethyl ether 74.12 -116.3 0.714 4.00 ml Benzaldehyde 106.1 26 1.04 0 200 g 'what is the limiting reactant? Choose. Molecular weight of stilbene product

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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7:27 O O @ X all 25% Submission Name: De Ocampo, Cyzvell N. Date: 11-30-21 Strand and Section: 12STEMA7 Teacher: Mr. Reynante S. Santos Homework 7.1| Stoichiometry in Chemical Reactions Directions: Use the balanced chemical equation to solve the following problems. 4Fe + 302 → 2FE203 1. How many moles of Fe,0z are produced when 7.27 grams of Fe is reacted? 1 mel Fe 2 mol Fe203 0.07 or 0.0650 mol Fe203 7.27 gFe 55.85 g Fe 4 mel Fe 2. How many moles of Fe,0, are produced when 19.0 grams of 0, is reacted? 1 mel02 2 Fe203 19:0 g02---- = 0.40 or 0.395 mol Fe203 32 g02 3 mele2 3. How many moles of 0, are needed to react with 25.9 grams of Fe? 1 met-Fe 3 mol 02 = 0.35 mol 02 25.9 Fe 55.85 g Fe 4 met Fe COMMENTS FILES (1) RUBRIC
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30) What is the percent yield for the reaction below? Only 28.16 g of CO2 are observed to have formed even though stoichiometry would predict the production of 225.3 g of CO2 since 4.000 X100 moles of C3H18 and 8.000 moles of O2 were used. 2 C8H18+ 25 O2 → 16 CO2 + 18 H2O A) 12.50% B) 25.00% C) 50.00% 20.00%
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Remaining Time: 1 hour, 01 minute, 47 seconds. * Question Completion Status: QUESTION 2 The number of water molecules in 2.3 mg of water is O 6.02 x 1023 O 77.0 x 1023 O 7.7 x 1023 O 7.7 x 1019 none of the above QUESTION 3 A ctudent makes a colution bu discolvina 254a ofNDOH int0 450 gof water Wh. Click Save and Submit to save and submit. Click Save All Answers to save all answer ere to search DELL
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& Esc 76°F Rain 1 7 Calculate the percent yield when: Theoretical yield = 4.5 g; Actual yield = 3.78 g O O O O F2 120% 2 0.12% 8.4% 84% # 3 $ 4 F5 D E % 5 T Search F7 6 F8 & 7 COCO F9 8 F10 P
Chemistry o 12 What mass of CO₂ will be produced from reaction of 6.00 g C₂H6 and excess O2? 2 C₂H6+502-4CO₂+ 3 H₂O C₂H6 02 CO₂ H₂O Molar Mass (g/mol) 30.07 32.00 44.01 18.02 8.79 17.5 12.00 8.20
How to calculate percent yield of this product? Final product: the Nitrated Methyl benzoate