If you have 255 mg of 1,3-bis(bromomethyl)benzene and 75 mg NaCN, what is the theoretical yield for the reaction shown below? (Hint: Determine the limiting reagent first.) NaCN Br. Br DMSO NC. CN Useful information: 1,3-bis(bromomethyl)benzene molar mass = 263.96 g/mol NaCN molar mass = 49.01 g/mol product molar mass = 156.19 g/mol O 120 mg O 239 mg O 151 mg O 302 mg

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Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
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If you have 255 mg of 1,3-bis(bromomethyl)benzene and 75 mg NaCN, what is the theoretical yield
for the reaction shown below? (Hint: Determine the limiting reagent first.)
NaCN
Br.
Br
DMSO
NC
CN
Useful information:
1,3-bis(bromomethyl)benzene molar mass = 263.96 g/mol
NaCN molar mass = 49.01 g/mol
product molar mass = 156.19 g/mol
O 120 mg
O 239 mg
O 151 mg
302 mg
Transcribed Image Text:If you have 255 mg of 1,3-bis(bromomethyl)benzene and 75 mg NaCN, what is the theoretical yield for the reaction shown below? (Hint: Determine the limiting reagent first.) NaCN Br. Br DMSO NC CN Useful information: 1,3-bis(bromomethyl)benzene molar mass = 263.96 g/mol NaCN molar mass = 49.01 g/mol product molar mass = 156.19 g/mol O 120 mg O 239 mg O 151 mg 302 mg
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