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Item 4: Hydrogen sulfide is an impurity in natural gas that must be removed. One common removal method is called the Claus process, which relies on the reaction given. Under optimal conditions the Claus process gives 98% yield of S8 from H2S. H= 1.01 amu S- 32 amu 0 - 16 amu If you started with 30.0 g of H2S and 50.0 g of 02, how many grams of S8 would be produced experimentally, assuming 98% yield * 8 H,Sg) + 40,(g) – $,() + 8 H,O(g) Your answer

Item 4: Hydrogen sulfide is an impurity in natural gas that must be removed. One common removal method is called the Claus process, which relies on the reaction given. Under optimal conditions the Claus process gives 98% yield of S8 from H2S. H= 1.01 amu S- 32 amu 0 - 16 amu If you started with 30.0 g of H2S and 50.0 g of 02, how many grams of S8 would be produced experimentally, assuming 98% yield * 8 H,Sg) + 40,(g) – $,() + 8 H,O(g) Your answer

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Item 4: Hydrogen sulfide is an impurity in natural gas that must be removed. One common removal method is called the Claus process, which relies on the reaction given. Under optimal conditions the Claus process gives 98% yield of S8 from H2S. H = 1.01 amu S= 32 amu 0 = 16 amu If you started with 30.0 g of H2S and 50.0 g of 02, how many grams of S8 would be produced experimentally, assuming 98% yield * 8 H,S(g) + 40,(g) – Są() + 8 H,O(g) Your answer
Transcribed Image Text:Item 4: Hydrogen sulfide is an impurity in natural gas that must be removed. One common removal method is called the Claus process, which relies on the reaction given. Under optimal conditions the Claus process gives 98% yield of S8 from H2S. H = 1.01 amu S= 32 amu 0 = 16 amu If you started with 30.0 g of H2S and 50.0 g of 02, how many grams of S8 would be produced experimentally, assuming 98% yield * 8 H,S(g) + 40,(g) – Są() + 8 H,O(g) Your answer
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