Item 4: Hydrogen sulfide is an impurity in natural gas that must be removed. One common removal method is called the Claus process, which relies on the reaction given. Under optimal conditions the Claus process gives 98% yield of S8 from H2S. H= 1.01 amu S- 32 amu 0 - 16 amu If you started with 30.0 g of H2S and 50.0 g of 02, how many grams of S8 would be produced experimentally, assuming 98% yield * 8 H,Sg) + 40,(g) – $,() + 8 H,O(g) Your answer

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Item 4: Hydrogen sulfide is an impurity in natural gas that must be removed. One
common removal method is called the Claus process, which relies on the
reaction given. Under optimal conditions the Claus process gives 98% yield of S8
from H2S.
H = 1.01 amu
S= 32 amu
0 = 16 amu
If you started with 30.0 g of H2S and 50.0 g of 02, how many grams of S8 would
be produced experimentally, assuming 98% yield *
8 H,S(g) + 40,(g) – Są() + 8 H,O(g)
Your answer
Transcribed Image Text:Item 4: Hydrogen sulfide is an impurity in natural gas that must be removed. One common removal method is called the Claus process, which relies on the reaction given. Under optimal conditions the Claus process gives 98% yield of S8 from H2S. H = 1.01 amu S= 32 amu 0 = 16 amu If you started with 30.0 g of H2S and 50.0 g of 02, how many grams of S8 would be produced experimentally, assuming 98% yield * 8 H,S(g) + 40,(g) – Są() + 8 H,O(g) Your answer
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