Need help asap In one experiment, 12.0 g of PCl5 was slowly added to 15.0 g of H2O according to the following balanced chemical equation: Pcl5(s)+4H2O(l) ---> H3PO4 (aq) + 5HCl (g) The molar masses for each compounds in the equation are as follows; PCl5: 208.224 g/mol H2O: 18.015 g/mol H3PO4: 97.994 g/mol HCl; 36.45 g/mol What is the limiting reagent in this scenario? solve the problem Exactly like the example attached.
Need help asap In one experiment, 12.0 g of PCl5 was slowly added to 15.0 g of H2O according to the following balanced chemical equation: Pcl5(s)+4H2O(l) ---> H3PO4 (aq) + 5HCl (g) The molar masses for each compounds in the equation are as follows; PCl5: 208.224 g/mol H2O: 18.015 g/mol H3PO4: 97.994 g/mol HCl; 36.45 g/mol What is the limiting reagent in this scenario? solve the problem Exactly like the example attached.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter3: Stoichiometry
Section: Chapter Questions
Problem 7RQ: Consider the hypothetical reaction between A2 and AB pictured below. What is the balanced equation?...
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In one experiment, 12.0 g of PCl5 was slowly added to 15.0 g of H2O according to the following balanced chemical equation:
Pcl5(s)+4H2O(l) ---> H3PO4 (aq) + 5HCl (g)
The molar masses for each compounds in the equation are as follows;
PCl5: 208.224 g/mol
H2O: 18.015 g/mol
H3PO4: 97.994 g/mol
HCl; 36.45 g/mol
What is the limiting reagent in this scenario?
solve the problem Exactly like the example attached.
Transcribed Image Text:Scenario #1
How many grams of silver chloride (AgCl) are produced from the reaction between
100.0 g of silver nitrate (AgNO,) and 100.0 g barium chloride (BaCl₂) ??
2AgNO3(s) + BaCl₂ (s)
moles
liters
100.0 g
100 g BaCl2 x
100.0 g
Determine the number of moles of product that can be created from 100 g of AgNO₂:
100.0 g-AgNO3 x
1 mole AgNO3
169.87 moles AgNO3
What is the
limiting reactant?
AgNO3
Ba(NO3)2 (5) + 2AgCl (s)
0.5887 moles
1 moles BaCl2
Determine the number of moles of product that can be created from 100 g of BaCl,:
2 moles AgC!
X
1mol Bach
208.23 g BaCl2
X
2 moles AgCl
2 moles AgNO3
0.5887 moles AgCl X 143.2 g AgCl
1 mole AgCl
MOLAR MASSES IF NEEDED:
169.87 g/mol
143,32 g/mol
213.341 g/mol
208.23 g/mol
0.58868 moles
- 200/333.74= 0.5887 moles AgCl
What is the maximum amount of
AgCl that can be formed?
AgNO.
AgCl
Ba(NO₂)₂
200.0/208.23 =
84.37 g AgCl
0.960476 moles AgCl
0.9606 molos
AgCl
0.5887 moles AgCl
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