For the reaction below, 64.5 g CaCO3 is mixed with 99.6 g of XCI. How many grams of CO2 will be produced? CaCO3 (s) + 2 XCI (aq) --> CaCl₂ (aq) + CO₂ (g) + X₂0 (1) You may not use all of the following molar mass information CaCO3 (s) = 100.09 g/mol XCI (aq) = 59.0 g/mol CaCl₂ (aq) = 110.98 g/mol CO₂ (g) = 44.01 g/mol X₂O (I) = 98.12 g/mol Your answer should have 3 significant figures. Your Answer: Answer I units

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For the reaction below, 64.5 g CaCO3 is mixed with 99.6 g of XCI. How many grams
of CO₂ will be produced?
CaCO 3 (s) + 2 XCI (aq) --> CaCl₂ (aq) + CO₂ (g) + X₂O (1)
You may not use all of the following molar mass information
CaCO3 (s) = 100.09 g/mol
XCI (aq) = 59.0 g/mol
CaCl2 (aq) = 110.98 g/mol
CO₂ (g) = 44.01 g/mol
X₂O (I) = 98.12 g/mol
Your answer should have 3 significant figures.
Your Answer:
Answer
units
Transcribed Image Text:For the reaction below, 64.5 g CaCO3 is mixed with 99.6 g of XCI. How many grams of CO₂ will be produced? CaCO 3 (s) + 2 XCI (aq) --> CaCl₂ (aq) + CO₂ (g) + X₂O (1) You may not use all of the following molar mass information CaCO3 (s) = 100.09 g/mol XCI (aq) = 59.0 g/mol CaCl2 (aq) = 110.98 g/mol CO₂ (g) = 44.01 g/mol X₂O (I) = 98.12 g/mol Your answer should have 3 significant figures. Your Answer: Answer units
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