Balance each of the following: (please add 1 where needed - even though we usually do not) 1) 1 NaHCO3 (s) ----> 1 2) 1 NaHCO3 (s) ----> 1 1 NaHCO3 (s)----> 1 3) 2 1 4) 2 NaHCO3 (s) ----> 1 H2(g) + 2 C(s) + 3 02(g) Using a mass of 1.70 g baking soda you started with initially, calculate the mass (g) of solid product that should be produced for equation 3 above. Answer with two decimal places and do not include units. Please use: Na = 22.99; H = 1.008; C = 12.011 and O = 15.999 g/mole. 31.02 Using a mass of 0.63 g baking soda you started with initially, calculate the mass (g) of solid product that should be produced for equation 4 above. Answer with two decimal places and do not include units. Please use: Na = 22.99; H = 1.008; C = 12.011 and O = 15.999 g/mole. 0.26 H2O(g) H₂O(g) 2 NaOH (s) + Na2CO3(s) + + 2 Na(s) + Na2O(s) 1 1 CO2(g) CO2(g) CO2(g)

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Assuming you started with 3.23 g of sodium bicarbonate and your actual yield of solid product is 1.20g, which reaction is more likely to be the correct one?

 

### Balancing Chemical Equations and Calculating Product Mass

#### Balancing the Equations:
1. **Equation 1:**
   - Reaction: 1 NaHCOsub>3</sub> (s) → 1 NaOH (s) + 1 CO<sub>2</sub> (g)
   
2. **Equation 2:**
   - Reaction: 1 NaHCOsub>3</sub> (s) → 1 Na<sub>2</sub>CO<sub>3</sub> (s) + 1 CO<sub>2</sub> (g) + 1 H<sub>2</sub>O (g)
   
3. **Equation 3:**
   - Reaction: 2 NaHCOsub>3</sub> (s) → 1 Na<sub>2</sub>O (s) + 2 CO<sub>2</sub> (g) + 1 H<sub>2</sub>O (g)
   
4. **Equation 4:**
   - Reaction: 2 NaHCOsub>3</sub> (s) → 2 Na (s) + 1 H<sub>2</sub> (g) + 2 C (s) + 3 O<sub>2</sub> (g)

#### Product Mass Calculation:
1. **Equation 3 Calculation:**
   - Using a mass of 1.70 g of baking soda (NaHCO<sub>3</sub>), calculate the mass (g) of the solid product.
   - Given Data: Na = 22.99 g/mol; H = 1.008 g/mol; C = 12.011 g/mol; O = 15.999 g/mol
   - Answer: 31.02 g

2. **Equation 4 Calculation:**
   - Using a mass of 0.63 g of baking soda (NaHCO<sub>3</sub>), calculate the mass (g) of the solid product.
   - Given Data: Na = 22.99 g/mol; H = 1.008 g/mol; C = 12.011 g/mol; O = 15.999 g/mol
   - Answer: 0.26 g

#### Explanation:
- In each equation, we balance the number of atoms on both
Transcribed Image Text:### Balancing Chemical Equations and Calculating Product Mass #### Balancing the Equations: 1. **Equation 1:** - Reaction: 1 NaHCOsub>3</sub> (s) → 1 NaOH (s) + 1 CO<sub>2</sub> (g) 2. **Equation 2:** - Reaction: 1 NaHCOsub>3</sub> (s) → 1 Na<sub>2</sub>CO<sub>3</sub> (s) + 1 CO<sub>2</sub> (g) + 1 H<sub>2</sub>O (g) 3. **Equation 3:** - Reaction: 2 NaHCOsub>3</sub> (s) → 1 Na<sub>2</sub>O (s) + 2 CO<sub>2</sub> (g) + 1 H<sub>2</sub>O (g) 4. **Equation 4:** - Reaction: 2 NaHCOsub>3</sub> (s) → 2 Na (s) + 1 H<sub>2</sub> (g) + 2 C (s) + 3 O<sub>2</sub> (g) #### Product Mass Calculation: 1. **Equation 3 Calculation:** - Using a mass of 1.70 g of baking soda (NaHCO<sub>3</sub>), calculate the mass (g) of the solid product. - Given Data: Na = 22.99 g/mol; H = 1.008 g/mol; C = 12.011 g/mol; O = 15.999 g/mol - Answer: 31.02 g 2. **Equation 4 Calculation:** - Using a mass of 0.63 g of baking soda (NaHCO<sub>3</sub>), calculate the mass (g) of the solid product. - Given Data: Na = 22.99 g/mol; H = 1.008 g/mol; C = 12.011 g/mol; O = 15.999 g/mol - Answer: 0.26 g #### Explanation: - In each equation, we balance the number of atoms on both
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