16) According to the balanced chemical equation5 H2C20 4(aq) + 2 MnO4-(aq) + 6 H+(aq) →10 CO 2(g) + 2 Mn2+(aq) + 8 H2O()0.3500 grams of oxalic acid, H2C2O4 will react with__moles of permanganate, MnO4".A) 0.009718B) 0.001554C) 0.003887D) 0.007774

Given that: Mass of oxalic acid = 0.3500 g Molar mass of oxalic acid = 90.03 g/mol Moles of oxalic acid = 0.3500g÷90.03 g/mol = 0.003887 mol By reaction stochiometry: (2mol MnO4-/5mol H2C2O4)×0.003887mol H2C2O4 = 0.001554 mol MnO4- So, 0.001554 mol of permanganate can be prepared. Option B is correct.

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Chemistry

16) According to the balanced chemical equation 5 H2C20 4(aq) + 2 MnO4“(aq) + 6 H+(aq) →10 CO 2(g) + 2 Mn2+(aq) + 8 H2O(1) grams of oxalic acid, H2C2O4 will react with B) 0.001554 0.3500 _moles of permanganate, MnO4". A) 0.009718 C) 0.003887 D) 0.007774

16) According to the balanced chemical equation 5 H2C20 4(aq) + 2 MnO4“(aq) + 6 H+(aq) →10 CO 2(g) + 2 Mn2+(aq) + 8 H2O(1) grams of oxalic acid, H2C2O4 will react with B) 0.001554 0.3500 _moles of permanganate, MnO4". A) 0.009718 C) 0.003887 D) 0.007774

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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