The balanced equation below shows a simple way of manufacturing hydrogen gas in lab (you've done thisl). For your convenlence, the molar mass of each substance is shown below their formulas (in purple). Use this information to make the requested calculation: 2 Al(s) + 6 HCI(aq) -> 2 AICI3(aq) + 3 H2(g) 26.982 36.461 133.341 2.016 What volume of hydrogen gas, in mL, would be produced by the reaction of 922 mg of hydrochloric acid with excess aluminum metal?

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The balanced equation below shows a simple way of manufacturing hydrogen gas in lab (you've done thisl). For your convenience, the molar
mass of each substance is shown below their formulas (in purple). Use this information to make the requested calculation:
2 Al(s) + 6 HCI(aq) -> 2 AICI3(aq) + 3 H2(g)
26.982
36.461
133.341
2.016
What volume of hydrogen gas, in mL, would be produced by the reaction of 922 mg of hydrochloric acid with excess aluminum metal?
Transcribed Image Text:The balanced equation below shows a simple way of manufacturing hydrogen gas in lab (you've done thisl). For your convenience, the molar mass of each substance is shown below their formulas (in purple). Use this information to make the requested calculation: 2 Al(s) + 6 HCI(aq) -> 2 AICI3(aq) + 3 H2(g) 26.982 36.461 133.341 2.016 What volume of hydrogen gas, in mL, would be produced by the reaction of 922 mg of hydrochloric acid with excess aluminum metal?
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