One of the challenges astronauts face is in space travel is the build-up of carbon dioxide in their spacecraft. The average human exhales about 42.0 g of carbon dioxide per hour. One method to remove the excess carbon dioxide from the air is using solid lithium hydroxide: CO2(g) + 2 LiOH(s) → Li2CO3(2) + H2O(l) If a typical cannister of LiOH contains 750.0 g, how many hours will it last for one person before it has to be replaced?
One of the challenges astronauts face is in space travel is the build-up of carbon dioxide in their spacecraft. The average human exhales about 42.0 g of carbon dioxide per hour. One method to remove the excess carbon dioxide from the air is using solid lithium hydroxide: CO2(g) + 2 LiOH(s) → Li2CO3(2) + H2O(l) If a typical cannister of LiOH contains 750.0 g, how many hours will it last for one person before it has to be replaced?
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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One of the challenges astronauts face is in space travel is the build-up of carbon dioxide in their spacecraft. The average human exhales about 42.0 g of carbon dioxide per hour. One method to remove the excess carbon dioxide from the air is using solid lithium hydroxide:
CO2(g) + 2 LiOH(s) → Li2CO3(2) + H2O(l)
If a typical cannister of LiOH contains 750.0 g, how many hours will
it last for one person before it has to be replaced?
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