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A solution is made by dissolving 3.21 g of Cu(NO3)3 in 250.0 mL of water. Then, to make a more dilute solution, 5.00 mL of this solution was added to a 100 mL volumetric flask, which was filled to the mark with water. What is the molarity of the Cu(NO3)3 in the first solution, and what is the molarity of the Cu(NO3)3 in the second solution? First solution = i M

A solution is made by dissolving 3.21 g of Cu(NO3)3 in 250.0 mL of water. Then, to make a more dilute solution, 5.00 mL of this solution was added to a 100 mL volumetric flask, which was filled to the mark with water. What is the molarity of the Cu(NO3)3 in the first solution, and what is the molarity of the Cu(NO3)3 in the second solution? First solution = i M

Chemistry
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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View Policies Current Attempt in Progress A solution is made by dissolving 3.21 g of Cu(NO3)3 in 250.0 mL of water. Then, to make a more dilute solution, 5.00 mL of this solution was added to a 100 mL volumetric flask, which was filled to the mark with water. What is the molarity of the Cu(NO3)3 in the first solution, and what is the molarity of the Cu(NO3)3 in the second solution? First solution = i M
Transcribed Image Text:View Policies Current Attempt in Progress A solution is made by dissolving 3.21 g of Cu(NO3)3 in 250.0 mL of water. Then, to make a more dilute solution, 5.00 mL of this solution was added to a 100 mL volumetric flask, which was filled to the mark with water. What is the molarity of the Cu(NO3)3 in the first solution, and what is the molarity of the Cu(NO3)3 in the second solution? First solution = i M
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Formula

Molarity :   Molarity is one of the unit of concentration. It is defined as the number of moles of solute present per liter of the solution.

So,   Molarity= moles/volume

Again moles can be determined as-

Moles = mass/molar mass

The Molarity for the second solution can be found by using the equation as- 

C1 × V1 = C2 × V2

Here-

C1 = concentration of dilute solution 

V1 = volume of dilute solution

C2 =concentration of concentrate solution

V2 = volume of concentrate solution 

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