35.0 mL of 0.325 M AgNO3 is added to 50.0 mL of 0.125 M MgCl2. Assuming all volumesare additive, what will be the molarity of all ions in the solution after mixing and after anyreaction takes place? (AgCI is not present as ions since it is insoluble.)

Following formula will be applied to calculate the resultant molarity of the solution(M) :-…

Answered: 35.0 mL of 0.325 M AgNO3 is added to…

Chemistry

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ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

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35.0 mL of 0.325 M AgNO3 is added to 50.0 mL of 0.125 M MgCl2. Assuming all volumes
are additive, what will be the molarity of all ions in the solution after mixing and after any
reaction takes place? (AgCI is not present as ions since it is insoluble.)

Expert Solution

Step 1

Following formula will be applied to calculate the resultant molarity of the solution(M) :-

$M V = M_{1} V_{1} + M_{2} V_{2} M = \frac{M_{1} V_{1} + M_{2} V_{2}}{V} w h e r e, V = v o l u m e o f t h e r e s u l \tan t s o l u t i o n i . e . V = V_{1} + V_{2} T h e r e f o r e, M = \frac{M_{1} V_{1} + M_{2} V_{2}}{V_{1} + V_{2}} M_{1} = m o l a r i t y o f A g N O_{3} s o l u t i o n M_{2} = m o l a r i t y o f M g C l_{2} s o l u t i o n V_{1} = v o l u m e o f A g N O_{3} s o l u t i o n V_{2} = v o l u m e o f M g C l_{2} s o l u t i o n$

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