Match the hypothesis, df and alpha to the critical value(s) EH1: H #45, df = 38, a = 0.05 A. ±2.021 B. 1.701 - H1:H > 37, df = 28, a = 0.1 C.- 2.390 EH:H < 62, df = 60, a = 0.01 %3D
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- The following table provides values of the function f(x,y). However, because of potential; errors in measurement, the functional values may be slightly inaccurately. Using the statistical package included with a graphical calculator or spreadsheet and critical thinking skills, find the function f(x,y)=a+bx+cy that best estimate the table where a, b and c are integers. Hint: Do a linear regression on each column with the value of y fixed and then use these four regression equations to determine the coefficient c. x y 0 1 2 3 0 4.02 7.04 9.98 13.00 1 6.01 9.06 11.98 14.96 2 7.99 10.95 14.02 17.09 3 9.99 13.01 16.01 19.02High to centimeters and weight in kilograms are measured for 100 randomly selected adult males and range from the height of 131 to 189 cm and weights of 37 to 150 kg. let the predictor variable X be the first variable given. the 100 paired measurements yield X bar is equal to 167.31 cm, y bar is equal to 81.42 kg. R is equal to 0.335. P value equal to 0.001 and predicted y = -103+1.08x. find the best predictive value of predicted why wait given an adult male who is 150 cm tall use a 0.01 significance level.Arm circumferences (cm) and heights (cm) are measured from randomly selected adult females. The 139 pairs of measurements yield x = 31.99 cm, y = 163.33 cm, r= 0.032, P-value = 0.708, and y = 158 + 0.1703x. Find the best predicted value of y (height) given an adult female with an arm circumference of 35.0 cm. Let the predictor variable x be arm circumference and the response variable y be height. Use a 0.05 significance level. %3D ..... The best predicted value is cm. (Round to two decimal places as needed.)
- Arm circumferences (cm) and heights (cm) are measured from randomly selected adult females. The 146pairs of measurements yield x=34.69cm, y=163.25cm, r=0.075, P-value=0.368, and y=157+0.1826x. Find the best predicted value of y (height) given an adult female with an arm circumference of 40.0cm. Let the predictor variable x be arm circumference and the response variable y be height. Use a 0.05 significance level. The best predicted value is ____cm.MORE BENEFITS OF EATING ORGANIC Using specific data, we find a significant difference in the proportion of fruit flies surviving after 13 days between those eating organic potatoes and those eating conventional (not organic) potatoes. This exercise asks you to conduct a hypothesis test using additional data. In this case, we are testing Họ : Po = Pc Ha: Po > Pc where p, and p. represent the proportion of fruit flies alive at the end of the given time frame of those eating organic food and those eating conventional food, respectively. Use a 5 % significance level. Effect of Organic Bananas After 25 Days After 25 days, the proportion of fruit flies eating organic bananas still alive is 0.45 , while the proportion still alive eating conventional bananas is 0.42. The standard error for the difference in proportions is 0.029. What is the value of the test statistic? Round your answer to two decimal places. z = i What is the p-value? Round your answer to three decimal places. p-value = What…MORE BENEFITS OF EATING ORGANIC Using specific data, we find a significant difference in the proportion of fruit flies surviving after 13 days between those eating organic potatoes and those eating conventional (not organic) potatoes. This exercise asks you to conduct a hypothesis test using additional data. In this case, we are testing Họ : Po = Pc Ha: Po > Pc where p, and p. represent the proportion of fruit flies alive at the end of the given time frame of those eating organic food and those eating conventional food, respectively. Use a 5 % significance level. Effect of Organic Soybeans After 5 Days After 5 days, the proportion of fruit flies eating organic soybeans still alive is 0.92, while the proportion still alive eating conventional soybeans is 0.86. The standard error for the difference in proportions is 0.023. What is the value of the test statistic? Round your answer to two decimal places. Z = What is the p-value? Round your answer to three decimal places. p-value = i What…
- 13:33 ull ? A alms-cdn.gelisim.edu.tr exercise - A researcher wishes to try three different techniques to lower the blood pressure of individuals diagnosed with high blood pressure. The subject are randomly assigned to three groups; the first group takes medication, the second group exercises, and the third group follows a special diet. After four weeks, the reduction in each person's blood pressure is recorded. At a = 0.05, test the claim that there is no difference among the mea The data are shown: - Medication Exercise Diet 10 6. 12 8 9 9. 3 12 15 8 13 4. EPI8OSpring 2008Heights (cm) and weights (kg) are measured for 100 randomly selected adult males, and range from heights of 136 to 190 cm and weights of 39 to 150 kg. Let the predictor variable x be the first variable given. The 100 paired measurements yiel x= 167.51 cm, y = 81.36 kg,r= 0.232, P-value = 0.020, and y = - 103+ 1.13x. Find the best predicted value of y (weight) given an adult male who is 153 cm tall. Use a 0.01 significance level. The best predicted value of y for an adult male who is 153 cm tall is kg. (Round to two decimal places as needed.)Random sampling from four normally distributed populations produced the following data: (You may find it useful to reference the E table.) A -7 -13 -16 Treatments B -8 -9 -15 -4 Grand mean SSTR MSTR C -8 -11 -5 -9 -4 Click here for the Excel Data File a. Calculate the grand mean. (Negative value should be indicated by a minus sign. Round your answer to 2 decimal places.) D -9 -16 -17 b. Calculate SSTR and MSTR. (Round Intermediate calculations to at least 4 decimal places and final answers to 4 decimal places.)
