Arm circumferences (cm) and heights (cm) are measured from randomly selected adult females. The 139 pairs of measurements yield x = 31.99 cm, y = 163.33 cm, r= 0.032, P-value = 0.708, and y = 158 + 0.1703x. Find the best predicted value of y (height) given an adult female with an arm circumference of 35.0 cm. Let the predictor variable x be arm circumference and the response variable y be height. Use a 0.05 significance level. ..... The best predicted value is cm. (Round to two decimal places as needed.)
Arm circumferences (cm) and heights (cm) are measured from randomly selected adult females. The 139 pairs of measurements yield x = 31.99 cm, y = 163.33 cm, r= 0.032, P-value = 0.708, and y = 158 + 0.1703x. Find the best predicted value of y (height) given an adult female with an arm circumference of 35.0 cm. Let the predictor variable x be arm circumference and the response variable y be height. Use a 0.05 significance level. ..... The best predicted value is cm. (Round to two decimal places as needed.)
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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![**Transcription of Educational Content:**
**Topic: Predictive Modelling with Arm Circumferences and Heights**
In this study, arm circumferences (cm) and heights (cm) are measured from randomly selected adult females. The analysis includes 139 pairs of measurements which yield the following statistical data:
- Mean arm circumference (\( \bar{x} \)): 31.99 cm
- Mean height (\( \bar{y} \)): 163.33 cm
- Correlation coefficient (r): 0.032
- P-value: 0.708
- The regression equation is given by:
\[
\hat{y} = 158 + 0.1703x
\]
**Task:**
Find the best predicted value of \( \hat{y} \) (height) for an adult female with an arm circumference of 35.0 cm. Let the predictor variable \( x \) be arm circumference and the response variable \( y \) be height. Use a 0.05 significance level.
**Solution:**
The best predicted value is ______ cm.
(Round to two decimal places as needed.)
Note: There are no graphs or diagrams included in the content.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F776b81b2-5984-443d-93b2-d351507602c0%2Fea870e29-ba6b-48ab-881d-d70d2ef358ca%2F252pces_processed.png&w=3840&q=75)
Transcribed Image Text:**Transcription of Educational Content:**
**Topic: Predictive Modelling with Arm Circumferences and Heights**
In this study, arm circumferences (cm) and heights (cm) are measured from randomly selected adult females. The analysis includes 139 pairs of measurements which yield the following statistical data:
- Mean arm circumference (\( \bar{x} \)): 31.99 cm
- Mean height (\( \bar{y} \)): 163.33 cm
- Correlation coefficient (r): 0.032
- P-value: 0.708
- The regression equation is given by:
\[
\hat{y} = 158 + 0.1703x
\]
**Task:**
Find the best predicted value of \( \hat{y} \) (height) for an adult female with an arm circumference of 35.0 cm. Let the predictor variable \( x \) be arm circumference and the response variable \( y \) be height. Use a 0.05 significance level.
**Solution:**
The best predicted value is ______ cm.
(Round to two decimal places as needed.)
Note: There are no graphs or diagrams included in the content.
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