Random sampling from four normally distributed populations produced the following data: (You may find it useful to reference the E table.) A -7 -13 -16 Treatments B -8 -9 -15 -4 SSTR MSTR Grand mean C -11 -5 D -9 Click here for the Excel Data File a. Calculate the grand mean. (Negative value should be indicated by a minus sign. Round your answer to 2 decimal places.) -16 -17 b. Calculate SSTR and MSTR. (Round Intermediate calculations to at least 4 decimal places and final answers to 4 decimal places.)

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Random sampling from four normally distributed populations produced the following data: (You may find it useful to reference the F-table.)

|   | Treatments   |
|---|--------------|
|   | A  | B  | C  | D  |
|---|----|----|----|----|
|   | -7 | -8 | -8 | -9 |
|   | -13| -9 | -11| -16|
|   | -16| -15| -5 | -17|
|   | -4 | -9 |    | -4 |

[Click here for the Excel Data File]

a. Calculate the grand mean. (Negative value should be indicated by a minus sign. Round your answer to 2 decimal places.)

Grand mean: [Input Box]

b. Calculate \( SSTR \) and \( MSTR \). (Round intermediate calculations to at least 4 decimal places and final answers to 4 decimal places.)

|      |          |
|------|----------|
| \( SSTR \) | [Input Box] |
| \( MSTR \) | [Input Box] |
Transcribed Image Text:Random sampling from four normally distributed populations produced the following data: (You may find it useful to reference the F-table.) | | Treatments | |---|--------------| | | A | B | C | D | |---|----|----|----|----| | | -7 | -8 | -8 | -9 | | | -13| -9 | -11| -16| | | -16| -15| -5 | -17| | | -4 | -9 | | -4 | [Click here for the Excel Data File] a. Calculate the grand mean. (Negative value should be indicated by a minus sign. Round your answer to 2 decimal places.) Grand mean: [Input Box] b. Calculate \( SSTR \) and \( MSTR \). (Round intermediate calculations to at least 4 decimal places and final answers to 4 decimal places.) | | | |------|----------| | \( SSTR \) | [Input Box] | | \( MSTR \) | [Input Box] |
### Transcription for Educational Purposes

#### Statistical Analysis Task

**c.** Calculate SSE and MSE. *(Round intermediate calculations to at least 4 decimal places and final answers to 4 decimal places.)*

- **SSE**: [ ]  
- **MSE**: [ ]

**d.** Specify the competing hypotheses to determine whether some differences exist between the population means.

- \( H_0: \mu_A = \mu_B = \mu_C; \, H_a: \) Not all population means are equal.
- \( H_0: \mu_A \neq \mu_B \neq \mu_C; \, H_a: \) Not all population means are equal.
- \( H_0: \mu_A \leq \mu_B \leq \mu_C; \, H_a: \) Not all population means are equal.

**e-1.** Calculate the value of the \( F(d_{f1}, d_{f2}) \) test statistic. *(Round intermediate calculations to at least 4 decimal places and final answer to 3 decimal places.)*

- **Test statistic**: [ ]

**e-2.** Find the \( p \)-value.

- \( p \)-value ≥ 0.10
- 0.05 < \( p \)-value < 0.10
- 0.025 ≤ \( p \)-value ≤ 0.05
- \( p \)-value < 0.01
- 0.01 ≤ \( p \)-value < 0.025

**f.** At the 5% significance level, what is the conclusion to the test?

- Do not reject \( H_0 \) since the \( p \)-value is not less than the significance level
- Reject \( H_0 \) since the \( p \)-value is less than the significance level
Transcribed Image Text:### Transcription for Educational Purposes #### Statistical Analysis Task **c.** Calculate SSE and MSE. *(Round intermediate calculations to at least 4 decimal places and final answers to 4 decimal places.)* - **SSE**: [ ] - **MSE**: [ ] **d.** Specify the competing hypotheses to determine whether some differences exist between the population means. - \( H_0: \mu_A = \mu_B = \mu_C; \, H_a: \) Not all population means are equal. - \( H_0: \mu_A \neq \mu_B \neq \mu_C; \, H_a: \) Not all population means are equal. - \( H_0: \mu_A \leq \mu_B \leq \mu_C; \, H_a: \) Not all population means are equal. **e-1.** Calculate the value of the \( F(d_{f1}, d_{f2}) \) test statistic. *(Round intermediate calculations to at least 4 decimal places and final answer to 3 decimal places.)* - **Test statistic**: [ ] **e-2.** Find the \( p \)-value. - \( p \)-value ≥ 0.10 - 0.05 < \( p \)-value < 0.10 - 0.025 ≤ \( p \)-value ≤ 0.05 - \( p \)-value < 0.01 - 0.01 ≤ \( p \)-value < 0.025 **f.** At the 5% significance level, what is the conclusion to the test? - Do not reject \( H_0 \) since the \( p \)-value is not less than the significance level - Reject \( H_0 \) since the \( p \)-value is less than the significance level
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