Magnesium nitride, Mg3N2, can be produced from magnesium metal, Mg, and nitrogen gas, N2, in the following reaction: 3 Mg + N2 → Mg3N2 In a chemistry laboratory, you calculate the mass of available N2 to be 10.5 grams. After the reaction, you have produced 35.2 grams Mg3N2. Assuming you used a stoichiometric equivalent of Mg, what is the % yield of Mg3N2 in this reaction?

Chemistry for Engineering Students
4th Edition
ISBN:9781337398909
Author:Lawrence S. Brown, Tom Holme
Publisher:Lawrence S. Brown, Tom Holme
Chapter4: Stoichiometry
Section: Chapter Questions
Problem 4.43PAE: 4.43 Magnesium nitride forms in a side reaction when magnesium metal burns in air. This reaction may...
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Magnesium nitride, Mg3N2, can be produced from magnesium
metal, Mg, and nitrogen gas, N2, in the following reaction:
3 Mg + N2 → Mg3N2
In a chemistry laboratory, you calculate the mass of available N2 to
be 10.5 grams. After the reaction, you have produced 35.2 grams
Mg3N2. Assuming you used a stoichiometric equivalent of Mg, what
is the % yield of Mg3N2 in this reaction?
Transcribed Image Text:Magnesium nitride, Mg3N2, can be produced from magnesium metal, Mg, and nitrogen gas, N2, in the following reaction: 3 Mg + N2 → Mg3N2 In a chemistry laboratory, you calculate the mass of available N2 to be 10.5 grams. After the reaction, you have produced 35.2 grams Mg3N2. Assuming you used a stoichiometric equivalent of Mg, what is the % yield of Mg3N2 in this reaction?
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