M (kN.m) e. A cantilevered beam has of length L = 10 m and is subjected to a vertical load P₁ = 50 kN, an axial load P₂ = 100 kN passing through the neutral axis, a moment M = 200 kN.m, and a uniformly distributed load w = 30 kN/m, as shown. The cross-sectional view and dimensions are illustrated below, with point C representing the centroid of the cross-section. 300 mm W A x D W 2 L (m) P₁ ولا 25 mm Neutral Axis 200 mm P2 Support Material 50 mm M STRESS FORMULATION 25 mm N Normal stress: ON= Beam's cross-section M₂y Bending stress: Τρ Torsional shear stress: T= V, Q Transverse shear stress: T = It Q=YA' or Q= Draw the bending moment diagram for the beam. Show all your work. P₁ A L 42 D L (m) Neutral Axis P₂ M x (m) BEAM SIGN CONVENTION V V Positive internal shear M M Positive internal moment Beam sign convention CROSS-SECTIONAL MOMENTS OF INERTIA ABOUT THE CENTROID y bh³ Quadratic (second) 1,= ly = moment of inertia 12 hb³ 12 πρ 1₂ = ly=4 bh3+hb3 Polar moment of inertia 1x = 12 1x = 177 Σχιλι Centroid location: = Al Parallel axis theorem: ==Σ(1c₁ + A₁ d₁²)

Structural Analysis
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Chapter2: Loads On Structures
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M (kN.m)
e.
A cantilevered beam has of length L = 10 m and is subjected to a vertical load P₁ = 50 kN, an axial
load P₂ = 100 kN passing through the neutral axis, a moment M = 200 kN.m, and a uniformly
distributed load w = 30 kN/m, as shown. The cross-sectional view and dimensions are illustrated
below, with point C representing the centroid of the cross-section.
300 mm
W
A
x
D
W
2
L (m)
P₁
ولا
25 mm
Neutral Axis
200 mm
P2
Support Material
50 mm
M
STRESS FORMULATION
25 mm
N
Normal stress:
ON=
Beam's cross-section
M₂y
Bending stress:
Τρ
Torsional shear stress:
T=
V, Q
Transverse shear stress:
T = It
Q=YA'
or
Q=
Draw the bending moment diagram for the beam. Show all your work.
P₁
A
L
42
D
L (m)
Neutral Axis
P₂
M
x (m)
BEAM SIGN CONVENTION
V
V
Positive internal shear
M M
Positive internal moment
Beam sign convention
CROSS-SECTIONAL MOMENTS OF INERTIA ABOUT THE CENTROID
y
bh³
Quadratic (second)
1,=
ly =
moment of inertia
12
hb³
12
πρ
1₂ = ly=4
bh3+hb3
Polar moment of
inertia
1x =
12
1x = 177
Σχιλι
Centroid location:
= Al
Parallel axis theorem:
==Σ(1c₁ + A₁ d₁²)
Transcribed Image Text:M (kN.m) e. A cantilevered beam has of length L = 10 m and is subjected to a vertical load P₁ = 50 kN, an axial load P₂ = 100 kN passing through the neutral axis, a moment M = 200 kN.m, and a uniformly distributed load w = 30 kN/m, as shown. The cross-sectional view and dimensions are illustrated below, with point C representing the centroid of the cross-section. 300 mm W A x D W 2 L (m) P₁ ولا 25 mm Neutral Axis 200 mm P2 Support Material 50 mm M STRESS FORMULATION 25 mm N Normal stress: ON= Beam's cross-section M₂y Bending stress: Τρ Torsional shear stress: T= V, Q Transverse shear stress: T = It Q=YA' or Q= Draw the bending moment diagram for the beam. Show all your work. P₁ A L 42 D L (m) Neutral Axis P₂ M x (m) BEAM SIGN CONVENTION V V Positive internal shear M M Positive internal moment Beam sign convention CROSS-SECTIONAL MOMENTS OF INERTIA ABOUT THE CENTROID y bh³ Quadratic (second) 1,= ly = moment of inertia 12 hb³ 12 πρ 1₂ = ly=4 bh3+hb3 Polar moment of inertia 1x = 12 1x = 177 Σχιλι Centroid location: = Al Parallel axis theorem: ==Σ(1c₁ + A₁ d₁²)
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