Three small spherical masses are located in a plane at the positions shown below. Y (m) 4 3 2 1 0 -2 -3 S R -4 -5 -4 -3 -2 -1 8 1 X (m) 345 The masses are Q=0.800 kg, R=0.700 kg, and S=0.400 kg. Calculate the moment of inertia (of the 3 masses) with respect to an axis perpendicular to the xy plane and passing through x=0 and y=-3. [Since the masses are of small size, you can neglect the contribution due to moments of inertia about their centers of mass.] 28.8kg m^2

A 5-kg rod of uniform cross section is used to form the shaft shown. Knowing that the shaft rotates with a constant angular velocity ω of magnitude 12 rad/s, determine (a) the magnitude of angular momentum HG of the shaft about its mass center G, (b) the angle formed by HG and the axis AB.

The two spheres A and B each have a mass of 400 g. The spheres are fixed to the horizontal rods as shown in (Figure 1) and their initial velocity is 2 m/s. The mass of the supporting frame is negligible and it is free to rotate. Neglect the size of the spheres. Figure -0.3 m S M 0.3 m B 1 of 1 Part A If a couple moment of M = 0.9 Nm is applied to the frame, determine the speed of the spheres in 3 s. Express your answer to three significant figures and include the appropriate units. V= Value Submit μA Provide Feedback Request Answer Units ?

Please explain how to solve the moment of inertia with the solutions given (e.g. why is there a minus sign or a subtraction involved etc.)