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Step 1: Solve for the reactions at support A A H 19 18 IC 10 E Im 2m 2m 1m + Y ¥ Av 10 KN D KN 10kW Ev 1m 2m LEFT SECTION 616 SOLVE FOR REACTION AT SUPPORT IM₂ = 0 C+ Av (6) 10 (5)-10 (3)-10 (1)-0 ZFV = 0 ↑+ IS-10-10-10 + EV-0 Ev = 15 KN Step 2: Cut a section into a truss where the required forces are Note: You can only cut three members when using method of section. We have to first determine the slopes of GH and BG which are for GH is 2H:1V and for BG is 2H:3V. HS 2 Im BG √√13 2m 2 Анод BC B 2m- Av=15kW 10KW 9 Step 3: Solve for the forces required, BC,BG and GH *To determine BC we take summation of moment forces along G so that the other two unknowns BG and GH will be canceled G because their paths go to point

Step 1: Solve for the reactions at support A A H 19 18 IC 10 E Im 2m 2m 1m + Y ¥ Av 10 KN D KN 10kW Ev 1m 2m LEFT SECTION 616 SOLVE FOR REACTION AT SUPPORT IM₂ = 0 C+ Av (6) 10 (5)-10 (3)-10 (1)-0 ZFV = 0 ↑+ IS-10-10-10 + EV-0 Ev = 15 KN Step 2: Cut a section into a truss where the required forces are Note: You can only cut three members when using method of section. We have to first determine the slopes of GH and BG which are for GH is 2H:1V and for BG is 2H:3V. HS 2 Im BG √√13 2m 2 Анод BC B 2m- Av=15kW 10KW 9 Step 3: Solve for the forces required, BC,BG and GH *To determine BC we take summation of moment forces along G so that the other two unknowns BG and GH will be canceled G because their paths go to point

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Where √13 and √5 came from?
Step 1: Solve for the reactions at support A A H 19 18 IC 10 E Im 2m 2m 1m + Y ¥ Av 10 KN D KN 10kW Ev 1m 2m LEFT SECTION 616 SOLVE FOR REACTION AT SUPPORT IM₂ = 0 C+ Av (6) 10 (5)-10 (3)-10 (1)-0 ZFV = 0 ↑+ IS-10-10-10 + EV-0 Ev = 15 KN Step 2: Cut a section into a truss where the required forces are Note: You can only cut three members when using method of section. We have to first determine the slopes of GH and BG which are for GH is 2H:1V and for BG is 2H:3V. HS 2 Im BG √√13 2m 2 Анод BC B 2m- Av=15kW 10KW 9 Step 3: Solve for the forces required, BC,BG and GH *To determine BC we take summation of moment forces along G so that the other two unknowns BG and GH will be canceled G because their paths go to point
Transcribed Image Text:Step 1: Solve for the reactions at support A A H 19 18 IC 10 E Im 2m 2m 1m + Y ¥ Av 10 KN D KN 10kW Ev 1m 2m LEFT SECTION 616 SOLVE FOR REACTION AT SUPPORT IM₂ = 0 C+ Av (6) 10 (5)-10 (3)-10 (1)-0 ZFV = 0 ↑+ IS-10-10-10 + EV-0 Ev = 15 KN Step 2: Cut a section into a truss where the required forces are Note: You can only cut three members when using method of section. We have to first determine the slopes of GH and BG which are for GH is 2H:1V and for BG is 2H:3V. HS 2 Im BG √√13 2m 2 Анод BC B 2m- Av=15kW 10KW 9 Step 3: Solve for the forces required, BC,BG and GH *To determine BC we take summation of moment forces along G so that the other two unknowns BG and GH will be canceled G because their paths go to point
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