Step 1: Solve for the reactions at support A A H 19 18 IC 10 E Im 2m 2m 1m + Y ¥ Av 10 KN D KN 10kW Ev 1m 2m LEFT SECTION 616 SOLVE FOR REACTION AT SUPPORT IM₂ = 0 C+ Av (6) 10 (5)-10 (3)-10 (1)-0 ZFV = 0 ↑+ IS-10-10-10 + EV-0 Ev = 15 KN Step 2: Cut a section into a truss where the required forces are Note: You can only cut three members when using method of section. We have to first determine the slopes of GH and BG which are for GH is 2H:1V and for BG is 2H:3V. HS 2 Im BG √√13 2m 2 Анод BC B 2m- Av=15kW 10KW 9 Step 3: Solve for the forces required, BC,BG and GH *To determine BC we take summation of moment forces along G so that the other two unknowns BG and GH will be canceled G because their paths go to point
Step 1: Solve for the reactions at support A A H 19 18 IC 10 E Im 2m 2m 1m + Y ¥ Av 10 KN D KN 10kW Ev 1m 2m LEFT SECTION 616 SOLVE FOR REACTION AT SUPPORT IM₂ = 0 C+ Av (6) 10 (5)-10 (3)-10 (1)-0 ZFV = 0 ↑+ IS-10-10-10 + EV-0 Ev = 15 KN Step 2: Cut a section into a truss where the required forces are Note: You can only cut three members when using method of section. We have to first determine the slopes of GH and BG which are for GH is 2H:1V and for BG is 2H:3V. HS 2 Im BG √√13 2m 2 Анод BC B 2m- Av=15kW 10KW 9 Step 3: Solve for the forces required, BC,BG and GH *To determine BC we take summation of moment forces along G so that the other two unknowns BG and GH will be canceled G because their paths go to point
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
Related questions
Question
Where √13 and √5 came from?
![Step 1: Solve for the reactions at support
A A
H
19
18
IC
10
E
Im
2m
2m
1m
+
Y
¥
Av
10 KN
D KN
10kW
Ev
1m
2m
LEFT SECTION
616
SOLVE FOR REACTION AT SUPPORT
IM₂ = 0 C+
Av (6) 10 (5)-10 (3)-10 (1)-0
ZFV = 0 ↑+
IS-10-10-10 + EV-0
Ev = 15 KN
Step 2: Cut a section into a truss where the
required forces are
Note: You can only cut three
members when using method of section.
We have to first determine the
slopes of GH and BG which are for GH is
2H:1V and for BG is 2H:3V.
HS
2
Im
BG
√√13
2m
2
Анод
BC
B
2m-
Av=15kW
10KW
9
Step 3: Solve for the forces required, BC,BG
and GH
*To determine
BC
we take summation of moment forces along
G so that the other two unknowns BG and GH
will be canceled
G
because their paths go to point](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff6a47b5d-b7f6-472b-b973-fef39c6aa23e%2F5e5c82a7-31e0-4024-a9d1-affb3383fb95%2Fk9z6wps_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Step 1: Solve for the reactions at support
A A
H
19
18
IC
10
E
Im
2m
2m
1m
+
Y
¥
Av
10 KN
D KN
10kW
Ev
1m
2m
LEFT SECTION
616
SOLVE FOR REACTION AT SUPPORT
IM₂ = 0 C+
Av (6) 10 (5)-10 (3)-10 (1)-0
ZFV = 0 ↑+
IS-10-10-10 + EV-0
Ev = 15 KN
Step 2: Cut a section into a truss where the
required forces are
Note: You can only cut three
members when using method of section.
We have to first determine the
slopes of GH and BG which are for GH is
2H:1V and for BG is 2H:3V.
HS
2
Im
BG
√√13
2m
2
Анод
BC
B
2m-
Av=15kW
10KW
9
Step 3: Solve for the forces required, BC,BG
and GH
*To determine
BC
we take summation of moment forces along
G so that the other two unknowns BG and GH
will be canceled
G
because their paths go to point
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