१ AMPAD A 6717 B C D THE FOUR SIDED CLOSED TRAVERSE HAS THE FOLLOWING ANGLES & AB=713.93 FT. DISTANCES A= 51° 23' B= 105° 39' C = 78° 11' D= 124°47" BC = 606.06FT. CD = 391.27 FT. DA = 781.18 FT. THE AZIMUTH OF AB 15 67°17' 1. PERFORM A CHECK FOR ANGULAR MISCLOSURE (6Points) 2. COMPUTE AZIMUTHS FOR ALL SIDES (12 Points) 3. COMPUTE BEARINGS SIDES (12 POINTS) FOR ALL

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