LIFE SCIENCES/GRADE 10MDE/AUGUST 2024FETSECTION BQUESTION 22.1 The diagram below shows part of the nitrogen cycle and the water cycle.BA2.1.1 Identify the process at A where nitrogen in the atmosphere is converted into a usableform for plants.2.1.2 in which form is nitrogen absorbed by plants out of the ground at B?(1)(1)2.1.3 Which part of the water cycle is represented by C.(1)2.1.4 Runoff water from the farm into the river at D can cause excess nutrients / fertilizers toflow into the water. What is this phenomenon called?(1)2.1.5 Explain how the process mentioned in QUESTION 2.1.4 above might cause organismsto die in the river.࿉C(3)(7)COPY RIGHT RESERVEDPLEASE TURN OVER

2.1.1The process at A is nitrogen fixation. This is the conversion of atmospheric nitrogen gas (N2)…

Answered: LIFE SCIENCES/GRADE 10 MDE/AUGUST 2024…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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(LO 7.1.1, 7.1.2, 7.2.1, 7.2.2) A small home might use about 6.50 moles of methane, CH4, per day in moderately cold weather for heating. How many moles of water will be produced when combusting 6.50 moles of methane? CH4 + CO₂ + 2.17 3.25 4.33 6.5 9.75 13.0 19.5 0₂ → 111- H₂O (unbalanced)
This is possible because of the following reactions that take place rapidly as long as reactants are available: (11.3) Equation : 51-(aq) + IO-3(aq) + 6H+(aq) ----> 3I2(aq) +3H2O(I)
4 6. 8. 9. 10 Balance the chemical equation below using the smallest possible whole number stoichiometric coefficients. CH, (CH,) CH, (g) + 0,(g) – co,(g) + H,0(g)
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6. 7. 8.
Which of the following reactions would have a positive value for AS°? BaCO3(s) + H₂SO4(l) → BaSO4(s) + CO2(g) + H₂O(l) 1. 2. 3. 4. Na(s) → Na(1) 2 CO(g) + O2(g) →>>> 2 CO2(g) Pb(NO3)2(aq) + 2 HCl(aq) A. 3 only B. 1 and 4 C. 3 and 4 D. 1 and 2 E. 2 and 4 PbCl2(s) + 2 HNO3(aq)
(2.37) Based on the given data, set up the expression for Qp. Each reaction participant must be represented by one tile. Do not combine terms. Once the expression is constructed, solve for Qp. (2.37)² Consider the equilibrium system described by the chemical reaction below. Calculate the value of Qp for the initial set reaction conditions: 2.37 atm N₂, 4.18 atm O₂, 1.15 atm NO. N₂(g) + O₂(g) 2 NO(g) 0.232 (4.18) (4.18)² 0.116 = (1.15) (1.15)² 7.49 (4.74) (4.74)² 1 4.31 (8.36) (8.36)² = (2.30) (2.30)² (28.0) (30.0)² RESET (32.0) 0.133
Question 7.102
7:25 ◄ Search 1 Balance the following chemical equation (if necessary): 3c₂²- + SiCl4 (s) + H₂O(l) → H4SiO4(aq) + HCI (aq) Question 3 of 20 (s) HCI ( Reset 2 3 4 5 6 7 8 9 (1) H₂SiO4 H₂O (g) 5G 85 SICI4 Submit Tap here or pull up for additional resources (aq) 0 • x H₂O
T₂ H(T₂) = H(T) + [²C,dT T₁ T₂ A‚H°(T,) = A‚H°(T; ) + √„ª ACT (2C.6) Kirchhoff's law (2C.7a) P T₁ - Σ vcom - Σ vco AC = Σ VC - p,m Products Reactants p,m (2C.7b) 14. 14.1 14.2 14.3 Equation 2C.6 (prescribed textbook) can be written for both the reactants and the products. The difference between the resulting expressions is the Kirchhoff's law in 2C.7a (prescribed textbook). Write the reaction equation for the formation of cyclohexane, C6H12(e). Use equation 2C.7b (prescribed textbook) and the data in Resource section to calculate the difference of the molar heat capacities. [5 sig. fig.] Use Kirchhoff's law to calculate the standard enthalpy of formation of cyclohexane at 400 K from the data in Resource section. [5 sig. fig.]
7:25 ◄ Search 3c₂²- 1 Balance the following chemical equation (if necessary): C3H6O₂(g) + O₂(g) → H₂O(g) + CO₂ (g) + (s) Question 4 of 20 C3H6O2 ( Reset 2 3 4 5 6 7 8 9 (1) CO₂ 0₂ (g) 5G 85 H₂O Submit Tap here or pull up for additional resources (aq) 0 • x H₂O
3. 6.54 The conversion of (CH3)3CI to (CH3)2 C= CH2 Can occur by either one-step or two-step mechanism, as shown in Equations (1] and (2]. [1] + I + H2O: [2] Slow + H2O: PAssume Equation [2] represents an endothermíc reaction and that the product of the rate determining step higher in energy than the reactants or produts, is Draw an Labei the axes, recatants and products for each Step, and the Ea and AH° for each stop. Label AHoverall. Draw the Structure for both transition States. energy dagram for this two-step reaction.

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