(2.37) Based on the given data, set up the expression for Qp. Each reaction participant must be represented by one tile. Do not combine terms. Once the expression is constructed, solve for Qp. (2.37)² Consider the equilibrium system described by the chemical reaction below. Calculate the value of Qp for the initial set reaction conditions: 2.37 atm N₂, 4.18 atm O₂, 1.15 atm NO. N₂(g) + O₂(g) 2 NO(g) 0.232 (4.18) (4.18)² 0.116 Qp = (1.15) (1.15)² 7.49 (4.74) (4.74)² 1 4.31 (8.36) (8.36)² (2.30) (2.30)² (28.0) (30.0)² RESET (32.0) 0.133

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Chapter1: Chemical Foundations
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(2.37)
Based on the given data, set up the expression for Qp. Each reaction participant must be
represented by one tile. Do not combine terms.
Once the expression is constructed, solve for Qp.
(2.37)²
Consider the equilibrium system described by the chemical reaction
below. Calculate the value of Qp for the initial set reaction conditions:
2.37 atm N₂, 4.18 atm O₂, 1.15 atm NO.
N₂(g) + O₂(g) 2 NO(g)
0.232
(4.18)
(4.18)²
0.116
=
(1.15)
(1.15)²
7.49
(4.74)
(4.74)²
1
4.31
(8.36)
(8.36)²
=
(2.30)
(2.30)²
(28.0)
(30.0)²
RESET
(32.0)
0.133
Transcribed Image Text:(2.37) Based on the given data, set up the expression for Qp. Each reaction participant must be represented by one tile. Do not combine terms. Once the expression is constructed, solve for Qp. (2.37)² Consider the equilibrium system described by the chemical reaction below. Calculate the value of Qp for the initial set reaction conditions: 2.37 atm N₂, 4.18 atm O₂, 1.15 atm NO. N₂(g) + O₂(g) 2 NO(g) 0.232 (4.18) (4.18)² 0.116 = (1.15) (1.15)² 7.49 (4.74) (4.74)² 1 4.31 (8.36) (8.36)² = (2.30) (2.30)² (28.0) (30.0)² RESET (32.0) 0.133
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