For the reaction Fe2O3(g) + 3H2(g) 2Fe(s) + 3H2O(g) H =+ 98.7 kJ if the system is at equilibrium and the volume of the container is then decreased, the concentration of products will A) decrease because there are fewer moles of reactant than product. B) increase because there are fewer moles of product than reactant. C) remain the same. D) decrease because the pressure of H2O will increase and the reaction will to try to alleviate that increase in pressure. E) increase because the pressure of H2 will increase and the reaction will try to alleviate that increase in pressure.

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