Determine the rate law and rate constant for the following reaction. Don't forget the units. Some of the numbers are blurry. (The concentrations for H+ are x 10-5 and the rates are x 10-7 with the last value being x10-8) 103(aq) + 81(aq) + 6 H*(aq) → 31, (aq) + 2 H₂O(aq) Trial 1 [103] 0.0050 [I]. 0.030 [H]. 2.0 x 10 Initial Rate (M/s) 2.70 x 10 2 0.0100 0.030 2.0 x 10 5.40 x 10 3 0.0050 0.045 2.0 x 10 6.07 x 10 4 0.0050 0.030 1.0 x 10 6.75 x 10
Determine the rate law and rate constant for the following reaction. Don't forget the units. Some of the numbers are blurry. (The concentrations for H+ are x 10-5 and the rates are x 10-7 with the last value being x10-8) 103(aq) + 81(aq) + 6 H*(aq) → 31, (aq) + 2 H₂O(aq) Trial 1 [103] 0.0050 [I]. 0.030 [H]. 2.0 x 10 Initial Rate (M/s) 2.70 x 10 2 0.0100 0.030 2.0 x 10 5.40 x 10 3 0.0050 0.045 2.0 x 10 6.07 x 10 4 0.0050 0.030 1.0 x 10 6.75 x 10
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![Determine the rate law and rate constant for the following reaction. Don't forget the
units. Some of the numbers are blurry. (The concentrations for H+ are x 10-5 and
the rates are x 10-7 with the last value being x10-8)
103(aq) + 81(aq) + 6 H*(aq) → 31, (aq) + 2 H₂O(aq)
Trial
1
[103]
0.0050
[I].
0.030
[H].
2.0 x 10
Initial Rate (M/s)
2.70 x 10
2
0.0100
0.030
2.0 x 10
5.40 x 10
3
0.0050
0.045
2.0 x 10
6.07 x 10
4
0.0050
0.030
1.0 x 10
6.75 x 10](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Feccb998d-45d7-4c28-ac87-d12a95eaad07%2F9f7a2126-2c5f-44cf-9a66-b47005ec21db%2F5x74k9w_processed.png&w=3840&q=75)
Transcribed Image Text:Determine the rate law and rate constant for the following reaction. Don't forget the
units. Some of the numbers are blurry. (The concentrations for H+ are x 10-5 and
the rates are x 10-7 with the last value being x10-8)
103(aq) + 81(aq) + 6 H*(aq) → 31, (aq) + 2 H₂O(aq)
Trial
1
[103]
0.0050
[I].
0.030
[H].
2.0 x 10
Initial Rate (M/s)
2.70 x 10
2
0.0100
0.030
2.0 x 10
5.40 x 10
3
0.0050
0.045
2.0 x 10
6.07 x 10
4
0.0050
0.030
1.0 x 10
6.75 x 10
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