Let's consider a fixed supported beam subjected to a triangular distributed load as shown in the figure below. The equation of the shear force (0 < x < 2m) is given by:

Mechanics of Materials (MindTap Course List)
9th Edition
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Barry J. Goodno, James M. Gere
Chapter1: Tension, Compression, And Shear
Section: Chapter Questions
Problem 1.3.16P: A space truss is restrained at joints A, B. and C, as shown in the figure. Load P acts in the +z...
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200 N/m
2 m
Transcribed Image Text:200 N/m 2 m
Let's consider a fixed supported beam
subjected to a triangular distributed load as
shown in the figure below. The equation of
the shear force (0 < x < 2m) is given by:
2 m
Select one:
O v (x) = -400 X² + 400 (N)
O v (x) = -200 X² + 200 (N)
O v (x) = -150 X² +150 (N)
O v (x) = -50 x² +50 (N)
O v (x) = -250 X² +250 (N)
Transcribed Image Text:Let's consider a fixed supported beam subjected to a triangular distributed load as shown in the figure below. The equation of the shear force (0 < x < 2m) is given by: 2 m Select one: O v (x) = -400 X² + 400 (N) O v (x) = -200 X² + 200 (N) O v (x) = -150 X² +150 (N) O v (x) = -50 x² +50 (N) O v (x) = -250 X² +250 (N)
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