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Kindly help me to arrive and draw the need and particular drawing for this analysis and how to come up to this answer with proper solutions and drawing.

Kindly help me to arrive and draw the need and particular drawing for this analysis and how to come up to this answer with proper solutions and drawing.

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Kindly help me to arrive and draw the need and particular drawing for this analysis and how to come up to this answer with proper solutions and drawing.

 
wo Vcc 27KN 6.8KV 100PF Yo Mo-16 0.1 AF 9.7 KL' RL hie : 1:11u nfe = 75 fCH2: 5OKHZ Given: Find: RL { BW show all, your solus : Explanation: RL =hie x hfe = 1.1 x 75 = 82.5 ohm S= 1/ hfe = 1/ 75 = 0.0133 BW = hfe/hie = 75/ 1.1 = 68.18 To find the input impedance, we need to find the Thevenin equivalent of the circuit with the load removed. The Thevenin equivalent of the circuit is given by: RL = hie x hfe = 1.1 x 75 = 82.5 ohm S = 1/ hfe = 1/ 75 = 0.0133 BW = hfe/hie = 75/ 1.1 = 68.18
Transcribed Image Text:wo Vcc 27KN 6.8KV 100PF Yo Mo-16 0.1 AF 9.7 KL' RL hie : 1:11u nfe = 75 fCH2: 5OKHZ Given: Find: RL { BW show all, your solus : Explanation: RL =hie x hfe = 1.1 x 75 = 82.5 ohm S= 1/ hfe = 1/ 75 = 0.0133 BW = hfe/hie = 75/ 1.1 = 68.18 To find the input impedance, we need to find the Thevenin equivalent of the circuit with the load removed. The Thevenin equivalent of the circuit is given by: RL = hie x hfe = 1.1 x 75 = 82.5 ohm S = 1/ hfe = 1/ 75 = 0.0133 BW = hfe/hie = 75/ 1.1 = 68.18
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