In the circuit below I = 3245° mA. What is the KCL expression at node a following the %3D conventions we used in class? j1 KN ll I2 -j8 KO - 4 ΚΩ I 5430° mAI 5260° V

Introductory Circuit Analysis (13th Edition)
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ISBN:9780133923605
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a.) what is the KCL expression at node A and node B? I’m pretty sure it’s the first option for node A and option 3 for B, but I just want to make sure
N MIDS
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(Vd. (Vo-Vo)
345°mA
jiko
O (Va
(Va-Vb)
%3D
4k2
jiko
(V) (Va-Vo)
=D0
3445°mA
%3D
-
4kO
(V) Va-Vb)
-3445°mA
%3D
4kN
QUESTION 34
Problem Continues:
Transcribed Image Text:N MIDS Seanav videos .Lecture Recording... My Drive - Google... Question Completion Status: (Vd. (Vo-Vo) 345°mA jiko O (Va (Va-Vb) %3D 4k2 jiko (V) (Va-Vo) =D0 3445°mA %3D - 4kO (V) Va-Vb) -3445°mA %3D 4kN QUESTION 34 Problem Continues:
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In the circuit below I = 3245° mA. What is the KCL expression at node a following the
conventions we used in class?
Nj1 KN
ll
a
I,
-j8 KO
4 ΚΩ
5230° mAI
5260° V
(V2, (Va-Vb)
3245°mA =
4kO
jikn
Transcribed Image Text:New Tab ard.com/webapps/assessment/take/launch.jsp?course_assessment_id%3_168587_1&course_id%3D_69233_1&content . & Seanav videos .Lecture Recording... My Drive - Google.. * Question Completion Status: In the circuit below I = 3245° mA. What is the KCL expression at node a following the conventions we used in class? Nj1 KN ll a I, -j8 KO 4 ΚΩ 5230° mAI 5260° V (V2, (Va-Vb) 3245°mA = 4kO jikn
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