It was found that the units on the ocular micrometer and the units on the stage micrometer matched up 40 units to 1.0 mm at 100 power. (So 40 ocular units equals 1.0 mm.) If the wing of a dead fruit fly was measured to be 2.5 ocular micrometer units at a magnification of 100, what is the length of the wing in mm? What does mm stand for?
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It was found that the units on the ocular micrometer and the units on the stage micrometer matched up 40 units to 1.0 mm at 100 power. (So 40 ocular units equals 1.0 mm.) If the wing of a dead fruit fly was measured to be 2.5 ocular micrometer units at a magnification of 100, what is the length of the wing in mm? What does mm stand for?
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- It was found that the units on the ocular micrometer and the units on the stage micrometer matched up 40 units to 1.0 mm at 100 power. (So 40 ocular units equals 1.0 mm.) If the wing of a dead fruit fly was measured to be 2.5 ocular micrometer units at a magnification of 100, what is the length of the wing in mm?Consider a bi convex lens with radius of curvatures |R1| = 30 mm and |R2| = 180 mm, ct = 5 mm and glass is N-BK7. This is used as camera lens in order to image a man who is at 1 km away from the camera. We want to resolve 10 cm on his body. Assume that λ = 550 nm. Using zemax, determine the MTF value for the resolution of R = 80 lp / mm in image plane which is placed at paraxial focus. (Hint: First, find the diameter of the lens) Which one: a.32.1 % b.28.7 % c.12.3 % d.58.5 % e.46.8 % f.57.2 % g.20.9 % h.15.6 %You have carried out an experiment using the spectrophotometry concept. A solutioncontaining compound X is mixed with reagent 1 and then reagent 2. This mixture produces ablue colour whose absorbance (A) could be read at 550 nm. The results are shown below. If the standard solution (compound X) used have a concentration of 1 mM:1. Calculate the quantity of the standard compound X in μmoles for each test tube (1-7).
- It is possible to make a perfectly precise measurement?Explain.Assume that you have an “X” solution that you do not know its concentration. But you have other X solutions with known concentrations and you know X solution absorbs maximum light at 575 nm. To calculate the unknown solution concentration, you have done some spectrophotometric measurements and obtained data given below. Prepare a standard curve by using the absorbance of known concentrations (Hint: you can learn how to prepare a standard curve by using Excell from youtube). Calculate the concentration of unknown.A 25.0 mL aliquot was taken from a 500.0 mL sample of tonic water containing an unknown amount of quinine and diluted to a volume of 150.0 mL. At 347.5 nm, the fluorescence intensity of the diluted sample was measured as 89.3 on an arbitrary scale. Under similar conditions, a 25.0 ppm standard quinine solution had a fluorescence intensity of 173. Calculate the mass of quinine in the original tonic water sample. mass: mg * TOOLS x10
- (b) Table Q1 below provides optical measurements of samples with known concentrations of analyte (ten samples were measured and the average and standard deviation are presented). They are also represented graphically in Figure Q1, below the table. Analyte concentration (nM) 0.1 0.2 0.5 1 2 5 10 15 fluorescence intensity 300000 250000 200000 150000 100000 50000 0 0 Table Q1 Fluorescence intensity (average) 9300 9200 10800 19600 37200 90000 178000 224000 5 [Analyte]/nM 10 Standard deviation 2000 1200 1000 2000 10000 30000 25000 40000 15 Figure Q1. Signal intensity for different analyte concentrations. Error bars are standard deviation. (ii) Calculate the limit of detection (LOD) for this sensor. (iii) A patient sample measured using this biosensor in the diagnostic laboratory generates a signal of 142800. The coefficient of variation of the device is 5%. Explain whether the diagnostic lab would have the confidence to report that the sample has a concentration in analyte of 8 nM or…Using a good compound light microscope with a resolving of 0.3 micro meter a 10x ocular lens ,and a 100 x oil immersion lens, would you be able to discern two objects separated by 0.4 micro meter?0.2 micro meter? 300 neno meter ? Explain your reasoning.What is the HVL of tissue for 1.25 MeV gamma-rays. How many half-layers of tissue are in the human forearm (assume an average thickness of 10 cm of tissue). What is the reduction in intensity as a 1.25 MeV gamma-ray passes through 10 cm of tissue? Assume the density of tissue is 1 g/cm2.
- In UV/Visible spectrophotometer analysis for a multicomponent system, there are only two dyes used in the mixture, the two proportions should be totalled to 1.0. but on finding You got 0.6 in total. Explain the reasons for the difference.The following image is a scheme for serial dilutions prepared for spectrophotometric analysis. If the stock solution concentration is 0.05 % (v/v) can you calculate the other tube’s concentrations in % v/v? I've used this with direct dilutions, how would I use this on serial dilutions?What is the reason for the decrease in the ABS value over time when measuring in the spectrophotometer?