If the field diameter is 2.4 mm and there are 16 cells across the field of view when using the 40X objective, what is the true length of one cell in millimeters (mm)?

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Q: What is the diameter of field of view for the high-power objective in millimeters and micrometers?

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A: A. Average length of one cell = 2.4 mm/ 40=0.06 mm Under 60X = 40 cells, each is 0.06 mm in length

Q: How is 10^4 derived? Please show all calculation steps. # of cells per mL = (Average)*DF*10^4 %3D

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