An airline wants to select a computer software package for thereservation system. Four software packages (1,2,3,4) arecommercially available. The airline will choose the package thatbumps as few passengers, on average, as possible during a month.An experiment is set up in which each package is used to makereservations for 5 randomly selected weeks. A total of 20 weeks wasincluded in the experiment. The number of passengers bumped eachweek is obtained, which gives rise to the following output analysis asin Output 1. Based on Output 1, the total degrees of freedom areOutput 1ANOVASource of VariationBetween GroupsdfMSp-valueF crit212.48.304985 0.001474 3.2388673.Within Groups136.48.525Total348.81619

We have given that an experiment is set up in which each package is used to make reservations for 5…

Answered: included in the experiment. The number…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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An employment information service claims the mean annual salary for senior level product engineers is $96,000. The annual salaries (in dollars) for a random sample of 16 senior level product engineers are shown in the table to the right. At a=0.10, test the claim that the mean salary is $96.000. Complete parts (a) through (e) below. Assume the population is normally distributed (a) Identify the claim and state Ho and H₂. Ho Y M H₂ N ▼ (Type integers or decimals. Do not round.) The claim is the hypothesis. (b) Use technology to find the critical value(s) and identify the rejection region(s). The critical value(s) is/are to (Use a comma to separate answers as needed. Round to two decimal places as needed.). Choose the graph which shows the rejection region О А. 15-6.176 4 -ho to Q Q (c) Find the standardized test statistic, t The standardized test statistic is t- (Round to two decimal places as needed.) (d) Decide whether to reject or fail to reject the null hypothesis. Ho because the…
A geneticist was curious about the relationship between gender and dominant hand. They surveyed a random sample of 500 people. Here is a summary of the responses and the results from a chi-squared test: Chi-square test: Dominant hand vs. gender Men Women Right 207 227 Expected 208.32 225.68 Left 21 27 Expected 23.04 24.96 Ambidextrous 12 - Expected 8.64 9.36 X%3D2.876, DF 2, P-value 0.237 Assume that all conditions for inference were met. At the a = 0.05 significance level, what is the most appropriate conclusion to draw from this test? O This is convincing evidence that the distribution of dominant hand differs between the genders. O This isn't enough evidence to say that the distribution of dominant hand differs between the genders. O This is convincing evidence that dominant hand and gender are not independent. OThey lack evidence to say that dominant hand and gender are not independent. O Gender causes people to be more likely to be left- or right-handed.
Exercise on ANOVA 1. A dietition wanted to test three different diets to find out if the mean weight loss for each of these diets is the same. She randomly selected 21 overweight person, randomly divided them into three groups, and put each group on one of the three diets. The following table records the weights (In kg) loss by these persons after being on these diets for two months. Diet 1 Diet 2 Diet 3 15 11 9 8 16 17 17 9 11 7 16 8 26 24 15 12 20 6 8 19 14 a) We are to test if the mean weight lost by all persons on each of the three diets is the same. Write the null and alternative hypotheses. b) Show the rejection and nonrejection regions on the F distribution curve for a=0.025. c) Calculate SSB, SSW, and SST. d) What are the degrees of freedom for the numerator and denominator? e) Calculate the between-samples and within-samples variances. f) What is the critical value of F for α=0.025. g) What is the calculated value of the test statistic F? h) Write the ANOVA table for this…
Use the Stata output below to answer the following question. The data used in this analysis is from a sample of airlines. The variables used are: fare-avg price of a one-way fare, in dollars dist- distance of the flight, in miles .reg fare ldist. Source Model Residual 551.391705 Total lfare SS ldist _cons 875.094374 df The OLS results suggest that 1 323.702668 120024315 4,594 MS Coef. Std. Err. 4,595 190444913 Number of obs F(1, 4594) Prob > F R-squared Adj R-squared Root MSE t P>|t| .4025646 .0077517 51.93 0.000 2.399834 .0521601 46.01 0.000 4,596 2696.98 0.0000 0.3699 0.3698 .34645 [95% Conf. Intervall .3873676 .4177617 2.297575 2.502093 a 1% increase in distance is associated with approximately a $.40 increase in the price of the fare. a 1% increase in distance is associated with approximately a .40% increase in the price of the fare. a 1% increase in distance is associated with approximately a 40 % increase in the price of the fare. None of the above.
I need help making a relative frequency histogram from this data.
The ANOVA table of the above data is as follows: ANOVA Source of Variation SS df MS 2.083 P-value Factor A J 1 0.725 Marketing startegies 0.750 1 0.750 0.832 Interaction 90.750 K 90.750 0.043 Within 125.333 15.667 Total 218.917 10. Calculate J and L 11. State HO and H1 hypotheses of interaction effect based on the above problem. 12. At a = 0.1, is there any significant effect? What is your decision? Support your answer. 13. What is your conclusion?
Locate the following percentile under the normal curve and find its corresponding t-value. Sketch and label its curve. 1. P95 degree of freedom 6 2. P99 degree of freedom 13 3. P89 degree of freedom 10
Clinical tests of the allergy drug Seldane yielded the results summarized in the table below. At the 5%5% significance level, test to determine if there is a relationship between the use of the drug and the occurrence of headaches. Seldane Users Placebo Users Control Total Headache 42 56 60 158 No headache 760 682 635 2077 Total 802 738 695 2235 Perform a Chi-squared test in the following steps: Step 1: State the null and alternative hypotheses: H0:H0:There is between the use of the drug Seldane and the occurrence of headaches. H1:H1: There is between the use of the drug Seldane and the occurrence of headaches. Step 2: Find the critical value(s): State αα-value (in decimals) with the degree(s) of freedom, separated by a comma. State the critical value(s): CV= (Do not round the table value.) Step 3. State the rejection region: Which area(s) is/are rejection region(s)? Reject H0H0 if test statistic value the critical value(s).…
4. 0 There is some indication that as countries' levels of literacy increases, authoritarian tendencies decline among the population. The following data show literacy (measured in number of literate people per 10 people) and authoritarian scores on a standard authoritarinaism- measuring scale from 8 countries. The data are: Xiiteracy : 9.2, 7.5, 8.8, 6.5, 4.3, 5.9, 9.7, 8.5 XAuth: 2.1, 3.4, 2.5, 7.3, 8.9, 5.7, 1.3, 2.5 Is there a reliable relationship between the two variables? If yes, what would the predicted authoritarian score of a country where only quarter of the country is literate? What about for a country where the literacy rate is %100? Use alpha = .05.
Fifty-four wild bears were anesthetized, and then their weights and chest sizes were measured and listed in a data set. Results are shown in the accompanying display. Use a significance level of x = 0.05 to answer the following questions. Correlation Results Correlation coeff, r: Critical r: P-value (two tailed): 0.000 Identify the correlation coefficient, r. r= (Round to three decimal places as needed.) Identify the critical value(s). (Round to three decimal places as needed.) OA. There are two critical values at r= ± OB. There is one critical value at r= Is there sufficient evidence to support the claim that there is a linear correlation between the weigh of bears and their chest sizes? Choose the correct below and, if necessary, fill in the answer box within your choice. (Round to three decimal places as needed.) exceeds the critical value. A. No, because the absolute value of r= OB. Yes, because the absolute value of r= OC. No, because r= exceeds the positive critical value. falls…
Refer to the below table. Using an alpha = 0.05, test the claim that IQ scores are the same for children in three different blood lead level groups: low lead level, medium lead level, and high lead level). One-Way Analysis of Variance Summary Table for IQ Measurements for Children among Three Blood Lead Level Groups: Low Lead Level, Medium Lead Level, and High Lead Level. Source df SS MS F p Between-group (treatment) 2 469.1827 2677.864 2.30 0.104 Within-group (error) 118 203.6918 11745.05 Total 120
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