included in the experiment. The number of passengers bumped each week is obtained, which gives rise to the following output analysis as in Output 1. Based on Output 1, the total degrees of freedom are Output 1 ANOVA Source of Variation Between Groups df MS F p-value F crit 212.4 8.304985 0.001474 3.238867 3 Within Groups 136.4 8.525 Total 348.8 O 16 O 19
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- A physical therapist wanted to know whether the mean step pulse of men was less than the mean step pulse of women. She randomly selected 54 men and 70 women to participate in the study. Each subject was required to step up and down a 6-inch platform. The pulse of each subject was then recorded. The following results were obtained. Two sample T for Men vs Women N Mean StDev SE Mean Men Women 98% CI for mu Men - mu Women (- 12.20, - 1.00) T-Test mu Men = mu Women (vs H2 O C. Ho: H1 = H2; Ha: H1 #H2 (b) Identify the P-value and state the researcher's conclusion if the level of significance was a = 0.01. What is the P-value? P-value =aaai 15 Concrete factory produces ten types of concrete products shown in the table below. if all types of concrete products have the same standard deviation, which type has the least ?relative variation Concrete 1. 2. 4 6. 7. 10 Products Мean 150 300 375 160 325 270 160 275 165 275 weight (KE) type 1 type 2 type 3 type 4 type 5 type 6 type 7 type 8 type 9 type 10A local veterinarian uses Z-scores to determine if newborn puppies of certain breeds are severely underweight, underweight, overweight, severely overweight, or within a typical weight range for their breed. Z-score Diagnosis Severely underweight Between -4.0 and -3.0 Underweight Less than -4.0 Between -3.0 and 3.0 Within the normal range Between 3.0 and 4.0 Overweight Severely overweight Greater than 4.0 Breed Mean (pounds) Standard deviation (pounds) Siberian Husky 23.2 2.5 Golden Retriever 31.5 2.1 Chow Chow 18.5 2.4 Shiba Inu 13.9 1.2 (a) What values would be considered to be normal for a hypothetical Siberian Husky puppy? Between and Enter an integer or decimal number (more. Report these answers to one decimal place (nearest tenth). (b) Show calculations and explain your reasoning.
- Use the Stata output below to answer the following question. The data used in this analysis is from a sample of airlines. The variables used are: fare-avg price of a one-way fare, in dollars dist- distance of the flight, in miles .reg fare ldist. Source Model Residual 551.391705 Total lfare SS ldist _cons 875.094374 df The OLS results suggest that 1 323.702668 120024315 4,594 MS Coef. Std. Err. 4,595 190444913 Number of obs F(1, 4594) Prob > F R-squared Adj R-squared Root MSE t P>|t| .4025646 .0077517 51.93 0.000 2.399834 .0521601 46.01 0.000 4,596 2696.98 0.0000 0.3699 0.3698 .34645 [95% Conf. Intervall .3873676 .4177617 2.297575 2.502093 a 1% increase in distance is associated with approximately a $.40 increase in the price of the fare. a 1% increase in distance is associated with approximately a .40% increase in the price of the fare. a 1% increase in distance is associated with approximately a 40 % increase in the price of the fare. None of the above.The ANOVA table of the above data is as follows: ANOVA Source of Variation SS df MS 2.083 P-value Factor A J 1 0.725 Marketing startegies 0.750 1 0.750 0.832 Interaction 90.750 K 90.750 0.043 Within 125.333 15.667 Total 218.917 10. Calculate J and L 11. State HO and H1 hypotheses of interaction effect based on the above problem. 12. At a = 0.1, is there any significant effect? What is your decision? Support your answer. 13. What is your conclusion?A company manufactures an electrical cooling fan. When the fans are performing properly, samples of 200 fans average 12.5 watts with an average range of 1.2 watts. A 3σ control chart program is being used to monitor the performance of the fans, and these data from the 10 most recent samples were collected: Sample Number Sample Mean Sample Range 1 12.5 1.1 2 12.45 1.2 3 12.55 0.9 4 12.50 0.8 5 12.45 0.9 6 12.60 1.0 7 12.48 1.4 8 12.46 1.1 9 12.56 0.9 10 12.48 0.8 Compute the 3σ control limits and center line for an ⁻x chart. Compute the 3σ control limits and center line for an R chart. Plot the sample data on the ⁻x and R charts and decide if the performance of the fan is in control.
- 3.18. A manufacturer of television sets is interested in the effect on tube conductivity of four different types of coating for color picture tubes. A completely randomized experiment is conducted and the following conductivity data are obtained: Coating Type 1 234 2 4 143 152 134 129 Conductivity 150 137 132 132 141 149 136 127 146 143 127 129 (a) Is there a difference in conductivity due to coating type? Use a = 0.05. (b) Estimate the overall mean and the treatment effects. (c) Compute a 95 percent confidence interval estimate of the mean of coating type 4. Compute a 99 percent confidence interval estimate of the mean difference between coating types 1 and 4.To determine if their 1.33 centimeter galvanized pipes are properly adjusted, Fogarty Manufacturing has decided to use an X-Chart which uses the range to estimate the variability in the sample. Answer How to enter your answe Step 1 of 7: What is the Center Line of the control chart? Round your answer to three decimal places. THWNHO Va 10 Period obs1 obs2 obs3 obs4 obs5 Sample Mean Sample Range 1 1.34 1.29 1.35 1.33 1.35 1.3320 2 1.35 1.35 1.29 1.38 1.28 1.3300 3 1.3360 4 1.30 1.3340 5 1.34 1.35 1.32 1.33 1.34 1.36 1.29 1.37 1.35 1.29 1.31 1.33 1.32 1.31 1.32 1.34 1.38 1.3260 1.38 1.34 1.33 1.31 1.31 1.31 1,29 1.3180 1.3300 1.35 1.33 1.30 1.35 1.32 1.3300 1.34 1.3440 1.37 1.3080 1.35 1.37 1.28 1.36 1.37 1,29 1.30 1.28 1.30 1.32 1.29 1.36 1.38 1.3400 1.36 1.32 1.31 1.30 1.35 1.3280 1.29 1.37 1.35 1.32 1.32 1.35 1.35 1.34 1.32 1.34 1.32 1.36 1.29 1.32 1:35 1.3300 1.3400 1.3280 11 12 13 Table 14 Control Chart 15 Copy Table Average Values The average of the selected cell(s) is 1.340. Copy…(1) The following table summarizes the BMI collected for three different groups of a population. BMI N Mean SD Group A 100 21.6 2.1 Group B 100 24.8 1.8 Group C 100 27.9 1.3 Test the hypothesis whether there is a significant difference in the mean BMI scores among three groups. Use a = 0.05.
- A one-sample z-test compares a sample with 50 participants with mean 83 to a population with mean 80 and standard deviation 10. What is the effect size d? 0.1 0.3 0.5 0.7Refer to the below table. Using an alpha = 0.05, test the claim that IQ scores are the same for children in three different blood lead level groups: low lead level, medium lead level, and high lead level). One-Way Analysis of Variance Summary Table for IQ Measurements for Children among Three Blood Lead Level Groups: Low Lead Level, Medium Lead Level, and High Lead Level. Source df SS MS F p Between-group (treatment) 2 469.1827 2677.864 2.30 0.104 Within-group (error) 118 203.6918 11745.05 Total 120To determine if their 1.33 centimeter galvanized pipes are properly adjusted, Fogarty Manufacturing has decided to use an X-Chart which uses the range to estimate the variability in the sample. Answer Table Step 4 of 7: Use the following sample data, taken from the next time period, to determine if the process is "In Control" or "Out of Control". Observations: 1.4, 1.42, 1.38, 1.37, 1.4 Sample Mean: 1.394 Period 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 Control Chart Copy Table Average Values The average of the selected cell(s) is 1.340. Copy Value obs1 obs2 obs3 obs4 obs5 Sample Mean Sample Range 1.34 1.29 1.35 1.33 1.35 1.3320 1.35 1.35 1.29 1.38 1.28 1.3300 1.34 1.35 1.32 1.33 1.34 1.3360 1.36 1.29 1.37 1.35 1.30 1.3340 1.29 1.31 1.33 1.32 1.38 1.3260 1.31 1.32 1.31 1.31 1.3180 1.34 1.33 1.3300 1.38 1.31 1.29 1.34 1.35 1.33 1.30 1.35 1.32 1.3300 1.34 1.37. 1.28 1.36 1.3440 1.37 1.30 1.3080 1.37 1.29 1.30 1.28 1.35 1.36 1.32 1.31 1.32 1.29 1.36 1.38 1.3400 1.3280 1.30 1.35 1.32 1.32 1.29…