In an experiment designed to test the output levels of three different treatments, the following results were obtained: ST - 280, SSTR = 110, ng- 19. Set up the ANOVA table. (Round your values for MSE and F to two decimal places, and your p-value to four decimal places.) Source Sum Degrees of Freedom Mean p-value of Variation of Squares Square Treatments Error Total Test for any significant difference between the mean output levels of the three treatments. Use a - 0.05. State the null and alternative hypotheses. O Ho: H- H2 H3 H: Hq # Hz# Hg O Ho: Not all the population means are equal. O Ho: At least two of the population means are equal. H: At least two of the population means are different. H: Not all the population means are equal. Find the value of the test statistic. (Round your answer to two decimal places.) Find the p-value. (Round your answer to four decimal places.) D-value - State your conclusion. O Reject H. There is not sufficient evidence to conclude that the means of the three treatments are not equal. O Reject H. There is sufficient evidence to conclude that the means of the three treatments are not equal. O Do not reject Ho. There is not sufficient evidence to conclude that the means of the three treatments are not equal. O Do not reject H.. There is sufficient evidence to conclude that the means of the three treatments are not equal.
In an experiment designed to test the output levels of three different treatments, the following results were obtained: ST - 280, SSTR = 110, ng- 19. Set up the ANOVA table. (Round your values for MSE and F to two decimal places, and your p-value to four decimal places.) Source Sum Degrees of Freedom Mean p-value of Variation of Squares Square Treatments Error Total Test for any significant difference between the mean output levels of the three treatments. Use a - 0.05. State the null and alternative hypotheses. O Ho: H- H2 H3 H: Hq # Hz# Hg O Ho: Not all the population means are equal. O Ho: At least two of the population means are equal. H: At least two of the population means are different. H: Not all the population means are equal. Find the value of the test statistic. (Round your answer to two decimal places.) Find the p-value. (Round your answer to four decimal places.) D-value - State your conclusion. O Reject H. There is not sufficient evidence to conclude that the means of the three treatments are not equal. O Reject H. There is sufficient evidence to conclude that the means of the three treatments are not equal. O Do not reject Ho. There is not sufficient evidence to conclude that the means of the three treatments are not equal. O Do not reject H.. There is sufficient evidence to conclude that the means of the three treatments are not equal.
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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
Transcribed Image Text:In an experiment designed to test the output levels of three different treatments, the following results were obtained: SST = 280, SSTR = 110, n, = 19. Set up the ANOVA table. (Round your values for MSE and F to two decimal places, and your p-value to four decimal places.)
Degrees
of Freedom
Source
Sum
Mean
F
p-value
of Variation
of Squares
Square
Treatments
Error
Total
Test for any significant difference between the mean output levels of the three treatments. Use a = 0.05.
State the null and alternative hypotheses.
O Hoi Hq# Hz# H3
Ha: H1 = H2 = H3
O Ho: H1 = H2 = H3
O H: Not all the population means are equal.
Hai H1 = H2 = H3
O Ho: At least two of the population means are equal.
H: At least two of the population means are different.
O Ho: H1 = H2 = 43
H: Not all the population means are equal.
Find the value of the test statistic. (Round your answer to two decimal places.)
Find the p-value. (Round your answer to four decimal places.)
p-value =
State your conclusion.
O Reject H.. There is not sufficient evidence to conclude that the means of the three treatments are not equal.
O Reject H.. There is sufficient evidence to conclude that the means of the three treatments are not equal.
O Do not reject H.. There is not sufficient evidence to conclude that the means of the three treatments are not equal.
O Do not reject H.. There is sufficient evidence to conclude that the means of the three treatments are not equal.
Expert Solution
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Step 1
It is given that, there are 3 different treatments.
This is one-way ANOVA design.
We have to test whether there is a difference between the mean output levels of the three treatments or not.
We have to complete the ANOVA table.
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