In this question we will consider a finite potential well in which V = −V0 in the interval −L/2 ≤ x ≤ L/2, and V = 0 everywhere else (where V0 is a positive real number). For a particle with in the range −V0 < E < 0, write and solve the time-independent Schrodinger equation in the classically allowed and classically forbidden regions. Remember to keep the wavenumbers and exponential factors in your solutions real!
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In this question we will consider a finite potential well in which V = −V0 in the interval −L/2 ≤ x ≤ L/2, and V = 0 everywhere else (where V0 is a positive real number).
For a particle with in the range −V0 < E < 0, write and solve the time-independent Schrodinger equation in the classically allowed and classically forbidden regions. Remember to keep the wavenumbers and exponential factors in your solutions real!
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- A particle is constrained to move in an infinitely deep square potential well, spanning from 0 < x < a. Suppose we add a delta function bump in the center of the well to produce the perturbation: H0 = (x−a=2) (1) Where is a constant. Find the first order correction to the nth allowed value of the energy. Explain why there is no correction for even n.Show that the following wave function is normalized. Remember to square it first. Limits of integration go from -infinity to infinity. DO NOT SKIP ANY STEPS IN THE PROCEDUREExercise 6.4 Consider an anisotropic three-dimensional harmonic oscillator potential acy = { m (w² x ² + w} y² + w? 2²). V (x, y, z) = = m(o² x² + @z. (a) Evaluate the energy levels in terms of wx, @y, and (b) Calculate [Ĥ, Î₂]. Do you expect the wave functions to be eigenfunctions of 1²? (c) Find the three lowest levels for the case @x = @y= = 2002/3, and determine the degener- of each level.
- Solve the problem for a quantum mechanical particle trapped in a one dimensional box of length L. This means determining the complete, normalized wave functions and the possible energies. Please use the back of this sheet if you need more room.(a) Write down the wave functions for the three regions of the potential energy barrier (Figure 5.25) for E < U₁. You will need six coefficients in all. Use complex exponential notation. (b) Use the boundary conditions at x = 0 and at x = L to find four relationships among the six coeffi- cients. (Do not try to solve these relationships.) (c) Sup- pose particles are incident on the barrier from the left. Which coefficient should be set to zero? Why?The essence of the statement of the uniqueness theorem is that if we know the conditions the limit that needs to be met by the potential of the system, then we find the solution of the system , then that solution is the only solution that exists and is not other solutions may be found. If we know potential solutions of a system, can we determine the type of system that generate this potential? If so, prove the statement! If no, give an example of a case that breaks the statement!
- We can use a quartic function function to represent this potential as shown below. Using the first order perturbation theory for particle in a box, calculate the ground- state energy: V(2) = ca 0< x < b a. How large of an effect on the energy is the perturbation of a curved wall?A particle of mass m is confined within a finite square well of depth V0 and width L.Sketch this potential, together with the form of the wavefunction and probability density for a particle in the lowest energy state. Briefly outline the procedure you would follow to determine the total number of energy eigenstates that can exist within a given finite square well.Needs Complete solution with 100 % accuracy.
- what are the possible results that may be obtained upon measuring the property lz on a particle in a particular state, if its wavefunction is known to be Ψ, which is an eigenfunction of l2 such that l2Ψ=12ℏΨ? SHOW FULL AND COMPLETE PROCEDURE IN A CLEAR AND ORDERED WAYshow that the following wave function is normalized. Remember to square it first. Show full and complete procedureFind a potential function for F or determine that F is not conservative. (If F is not conservative, enter NOT CONSERVATIVE.) F = (2xy + 3, x2 – 22, -2y)