In the tricarboxylic acid cycle, L-malate is oxidized to oxaloacetate, using NAD+ as an oxidizing agent. Using the half reactions from the given table, what is the reaction of this reduction-oxidation? Oxaloacetate + NAD+ –→ L-Malate + NADH L-Malate + Oxaloacetate -- NAD* + NADH L-Malate + NAD+ – → Oxaloacetate + NADH L-Malate -- Oxaloacetate + NAD+ + NADH
In the tricarboxylic acid cycle, L-malate is oxidized to oxaloacetate, using NAD+ as an oxidizing agent. Using the half reactions from the given table, what is the reaction of this reduction-oxidation? Oxaloacetate + NAD+ –→ L-Malate + NADH L-Malate + Oxaloacetate -- NAD* + NADH L-Malate + NAD+ – → Oxaloacetate + NADH L-Malate -- Oxaloacetate + NAD+ + NADH
Biochemistry
6th Edition
ISBN:9781305577206
Author:Reginald H. Garrett, Charles M. Grisham
Publisher:Reginald H. Garrett, Charles M. Grisham
Chapter23: Fatty Acid Catabolism
Section: Chapter Questions
Problem 16P: Extending the Mechanism of Methylmalonyl-CoA Mutase to Similar Reactions Based on the mechanism for...
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L-Malate + NAD⁺ ← → Oxaloacetate + NADH |
Above is what i selected for the equation, but I don't know how to find ΔE'৹.
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