In the circuit of Fig. 8_1, which of the following statements is **true**?![circuit-diagram](circuit-diagram)**Circuit Diagram Description:**- The circuit includes a voltage source of \(8u(t)\) V.- There is a \(4\Omega\) resistor in series with the source, marked with current \(i_x\).- A \(2\Omega\) resistor is in parallel with a \(3H\) inductor, both connected directly.- Current through the \(2\Omega\) resistor is marked as \(i_R\), and through the \(3H\) inductor as \(i_L\).- Initial current through the inductor \(i_L(0) = 1A\)._Fig. 8_3_**Answer Choices:**- \(i_x(t)=(2 - 0.334e^{-0.444t}) \, u(t) \, (A)\)- \(i_L(t)=(4+ 3e^{-0.444t}) \, u(t) \, (A)\)- Time constant = 0.4 seconds- \(i_R(t)=2.5 \, e^{-0.444t} \, u(t) \, (A)\)

In the circuit of Fig. 8_1, which of the following statements is true? 8u(t)V 40 iL(0)=1A Fig. 8_3 ○i(t)-(2-0.334e-0.444t) u(t) (A) Ⓒi(t)-(4+ 3e-0.444t) u(t) (A) Time constant 0.4 seconds OiR(t)-2.5 e-0.444t u(t) (A) WIL 20 33H LIR

In the circuit of Fig. 8_1, which of the following statements is true? 8u(t)V 40 iL(0)=1A Fig. 8_3 ○i(t)-(2-0.334e-0.444t) u(t) (A) Ⓒi(t)-(4+ 3e-0.444t) u(t) (A) Time constant 0.4 seconds OiR(t)-2.5 e-0.444t u(t) (A) WIL 20 33H LIR

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Question

In the circuit of Fig. 8_1, which of the following statements is **true**?

![circuit-diagram](circuit-diagram)

**Circuit Diagram Description:**
- The circuit includes a voltage source of \(8u(t)\) V.
- There is a \(4\Omega\) resistor in series with the source, marked with current \(i_x\).
- A \(2\Omega\) resistor is in parallel with a \(3H\) inductor, both connected directly.
- Current through the \(2\Omega\) resistor is marked as \(i_R\), and through the \(3H\) inductor as \(i_L\).
- Initial current through the inductor \(i_L(0) = 1A\).

_Fig. 8_3_

**Answer Choices:**
- \(i_x(t)=(2 - 0.334e^{-0.444t}) \, u(t) \, (A)\)
- \(i_L(t)=(4+ 3e^{-0.444t}) \, u(t) \, (A)\)
- Time constant = 0.4 seconds
- \(i_R(t)=2.5 \, e^{-0.444t} \, u(t) \, (A)\)

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