2. Two signals, x,(7) and x₂(1), are defined as follows, 0 = {6 x₂(t)= 3 1 -2.5 x3 (1)= and are shown in Figure 2. Perform the convolution x3(t)*x4 (t) and plot the result in the time domain only. -2 A t -2≤1≤0 0 elsewhere -1.5 t -1 -0.5 (1)"x 3 2.5 2 1.5 1 0.5 -3t+15 0 4≤1≤5 0 elsewhere 1 Figure 2: x(1) and xa(t) for Problem 2. 2 t 3 4 5
2. Two signals, x,(7) and x₂(1), are defined as follows, 0 = {6 x₂(t)= 3 1 -2.5 x3 (1)= and are shown in Figure 2. Perform the convolution x3(t)*x4 (t) and plot the result in the time domain only. -2 A t -2≤1≤0 0 elsewhere -1.5 t -1 -0.5 (1)"x 3 2.5 2 1.5 1 0.5 -3t+15 0 4≤1≤5 0 elsewhere 1 Figure 2: x(1) and xa(t) for Problem 2. 2 t 3 4 5
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Transcribed Image Text:2. Two signals, x,(7) and x₂(7), are defined as follows,
1 = { 0
x₂(t)=
3
1
-2.5
x3 (1)=
and are shown in Figure 2. Perform the convolution x₂(t)*x4(t) and plot the result in the time
domain only.
-2
t -2≤1≤0
0 elsewhere
-1.5
t
-1
-0.5
(1)"x
3
2.5
2
1.5
1
0.5
-3t+15
0
0
1
Figure 2: x(1) and xe(t) for Problem 2.
4≤t≤5
elsewhere
2
t
3
4
5
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Step 1: State the given data.
VIEWStep 2: Defining the convolution.
VIEWStep 3: Finding the convolution for t <2.
VIEWStep 4: Finding the convolution for 2<t<=3.
VIEWStep 5: Finding the convolution for 3<t<=4.
VIEWStep 6: Finding the convolution for t >4.
VIEWStep 7: Plotting the convolution of x3(t) and x4(t).
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