a. Explain with the aid of diagrams, the operation of the circuit with the switch first in position 1, and then in position 2. b. Calculate the total current supplied to the circuit 65ms after the switch is moved to position 1. c. The time taken for the voltage across the coil to reach 75% of its initial value. d. The time taken for the coil to become fully energised. e. Calculate the peak voltage at the instant the switch is moved to position 2 (assuming steady state conditions have been achieved before switching). f. The potential difference across the 500 resistor after 20ms. g. Calculate the time taken for the coil current to fall to 20% of its normal running value after the switch is moved to position 2 (assuming steady state conditions have been achieved before switching). I
a. Explain with the aid of diagrams, the operation of the circuit with the switch first in position 1, and then in position 2. b. Calculate the total current supplied to the circuit 65ms after the switch is moved to position 1. c. The time taken for the voltage across the coil to reach 75% of its initial value. d. The time taken for the coil to become fully energised. e. Calculate the peak voltage at the instant the switch is moved to position 2 (assuming steady state conditions have been achieved before switching). f. The potential difference across the 500 resistor after 20ms. g. Calculate the time taken for the coil current to fall to 20% of its normal running value after the switch is moved to position 2 (assuming steady state conditions have been achieved before switching). I
Power System Analysis and Design (MindTap Course List)
6th Edition
ISBN:9781305632134
Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Chapter3: Power Transformers
Section: Chapter Questions
Problem 3.30P: Reconsider Problem 3.29. If Va,VbandVc are a negative-sequence set, how would the voltage and...
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100
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V1
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a. Explain with the aid of diagrams, the operation of the circuit with the switch first in
position 1, and then in position 2.
PDF-XChange
b. Calculate the total current supplied to the circuit 65ms after the switch is moved to
position 1.
f.
The potential difference across the 500 resistor after 20ms.
W
c. The time taken for the voltage across the coil to reach 75% of its initial value.
d. The time taken for the coil to become fully energised.
e. Calculate the peak voltage at the instant the switch is moved to position 2
(assuming steady state conditions have been achieved before switching).
hp
Inductor
470mH
g. Calculate the time taken for the coil current to fall to 20% of its normal running value after
the switch is moved to position 2 (assuming steády state conditions have been achieved
before switching).
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Repla
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Transcribed Image Text:gate
References Mailings Review View Help
Po
100
E
Paragraph
V1
12V
Hv
S
AaBbCcDdl AaBbCcl AaBbC AaBbCc
1 Notes -...
Body Text
Heading 1
Heading 2
R2
5002
ProjectWise
R1
100
O
Styles
a. Explain with the aid of diagrams, the operation of the circuit with the switch first in
position 1, and then in position 2.
PDF-XChange
b. Calculate the total current supplied to the circuit 65ms after the switch is moved to
position 1.
f.
The potential difference across the 500 resistor after 20ms.
W
c. The time taken for the voltage across the coil to reach 75% of its initial value.
d. The time taken for the coil to become fully energised.
e. Calculate the peak voltage at the instant the switch is moved to position 2
(assuming steady state conditions have been achieved before switching).
hp
Inductor
470mH
g. Calculate the time taken for the coil current to fall to 20% of its normal running value after
the switch is moved to position 2 (assuming steády state conditions have been achieved
before switching).
PDF
Find
Repla
Selec
Editing
Focus
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B) I(t) = Il(o) - (11(∞) - 11(0))e
C) Vl(t) =
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dt
= 470x1.2x
470X10-³
10
F) V(t) = I(t)R
E) Il(t)=1.2- 1.2e
10
470
= 47msec
50
6-6e7= v(50) = 3.92v
-10,
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12
Il(o)= = 1.2A
10
Il(0) = 0A
I(65) 1.2 (1-e
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Vl(t) =
I(65) = 0.9A
-10.
Vl(t) = 12x e 470
VI(T) = 75% of VI(0)
75
VI(T) = x12 = 9
100
-10.
9 = 12xe 470*7
T = 13.52
10x65
e 470)
470
5T 5x47x10-3 = 235ms
1 No Spac... Heading 1
47x10-3
1.2x470x10-3 t
Vl(t) = 12
W
hp
v(t) = (1.2 - 1.2e) 50
v(t) = 6.6e
50x10 a
v(50) = 6-6e 47x10-³
t
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Transcribed Image Text:ilable
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B) I(t) = Il(o) - (11(∞) - 11(0))e
C) Vl(t) =
D) T = 5
ldi(t)
dt
= 470x1.2x
470X10-³
10
F) V(t) = I(t)R
E) Il(t)=1.2- 1.2e
10
470
= 47msec
50
6-6e7= v(50) = 3.92v
-10,
Normal
12
Il(o)= = 1.2A
10
Il(0) = 0A
I(65) 1.2 (1-e
xem
Vl(t) =
I(65) = 0.9A
-10.
Vl(t) = 12x e 470
VI(T) = 75% of VI(0)
75
VI(T) = x12 = 9
100
-10.
9 = 12xe 470*7
T = 13.52
10x65
e 470)
470
5T 5x47x10-3 = 235ms
1 No Spac... Heading 1
47x10-3
1.2x470x10-3 t
Vl(t) = 12
W
hp
v(t) = (1.2 - 1.2e) 50
v(t) = 6.6e
50x10 a
v(50) = 6-6e 47x10-³
t
e7 = 12e7
Styles
PDF
AaBbCcL
Heading 2
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Editin
Focus
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