In each of the net ionic equations below, select which type of arrow should be used. Buffer equilibrium: HC2H3O2 [Select ] H + C2H3O2 Neutralization of the buffer with a base: HC2H3O2 + OH- [Select ] C2H3O2 + H2O Neutralization of the buffer with an acid: C2H3O2¯ + H* [ Select ] * HC2H3O2
In each of the net ionic equations below, select which type of arrow should be used. Buffer equilibrium: HC2H3O2 [Select ] H + C2H3O2 Neutralization of the buffer with a base: HC2H3O2 + OH- [Select ] C2H3O2 + H2O Neutralization of the buffer with an acid: C2H3O2¯ + H* [ Select ] * HC2H3O2
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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answer choices: reversible arrows, forward only arrow, or reverse only arrow
![In each of the net ionic equations below, select which type of arrow should be used.
**Buffer equilibrium:**
\[ \text{HC}_2\text{H}_3\text{O}_2 \quad [\text{Select}] \quad \text{H}^+ + \text{C}_2\text{H}_3\text{O}_2^- \]
**Neutralization of the buffer with a base:**
\[ \text{HC}_2\text{H}_3\text{O}_2 + \text{OH}^- \quad [\text{Select}] \quad \text{C}_2\text{H}_3\text{O}_2^- + \text{H}_2\text{O} \]
**Neutralization of the buffer with an acid:**
\[ \text{C}_2\text{H}_3\text{O}_2^- + \text{H}^+ \quad [\text{Select}] \quad \text{HC}_2\text{H}_3\text{O}_2 \]
**Explanation:**
In the equations above, a buffer consisting of acetic acid (\(\text{HC}_2\text{H}_3\text{O}_2\)) and its conjugate base (\(\text{C}_2\text{H}_3\text{O}_2^-\)) is being analyzed. The type of arrow indicates the nature of the chemical reaction: equilibrium, complete reaction, or non-reaction.
1. **Buffer Equilibrium:** This involves a reversible reaction where the weak acid (\(\text{HC}_2\text{H}_3\text{O}_2\)) partially dissociates into hydrogen ions (\(\text{H}^+\)) and acetate ions (\(\text{C}_2\text{H}_3\text{O}_2^-\)).
2. **Neutralization with a Base:** When a base (e.g., \(\text{OH}^-\)) is added to the buffer, it reacts with the acetic acid, converting it to its conjugate base (\(\text{C}_2\text{H}_3\text{O}_2^-\)) and water. This process generally involves a complete reaction.
3. **Neutralization with an Acid:** Adding an acid leads to the conversion of the acetate ion back to](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb7468297-7302-4b5f-b105-f3955aeb803c%2F6cec75ca-c981-4e66-ba01-e7a3328e5a22%2Ftfr592q_processed.jpeg&w=3840&q=75)
Transcribed Image Text:In each of the net ionic equations below, select which type of arrow should be used.
**Buffer equilibrium:**
\[ \text{HC}_2\text{H}_3\text{O}_2 \quad [\text{Select}] \quad \text{H}^+ + \text{C}_2\text{H}_3\text{O}_2^- \]
**Neutralization of the buffer with a base:**
\[ \text{HC}_2\text{H}_3\text{O}_2 + \text{OH}^- \quad [\text{Select}] \quad \text{C}_2\text{H}_3\text{O}_2^- + \text{H}_2\text{O} \]
**Neutralization of the buffer with an acid:**
\[ \text{C}_2\text{H}_3\text{O}_2^- + \text{H}^+ \quad [\text{Select}] \quad \text{HC}_2\text{H}_3\text{O}_2 \]
**Explanation:**
In the equations above, a buffer consisting of acetic acid (\(\text{HC}_2\text{H}_3\text{O}_2\)) and its conjugate base (\(\text{C}_2\text{H}_3\text{O}_2^-\)) is being analyzed. The type of arrow indicates the nature of the chemical reaction: equilibrium, complete reaction, or non-reaction.
1. **Buffer Equilibrium:** This involves a reversible reaction where the weak acid (\(\text{HC}_2\text{H}_3\text{O}_2\)) partially dissociates into hydrogen ions (\(\text{H}^+\)) and acetate ions (\(\text{C}_2\text{H}_3\text{O}_2^-\)).
2. **Neutralization with a Base:** When a base (e.g., \(\text{OH}^-\)) is added to the buffer, it reacts with the acetic acid, converting it to its conjugate base (\(\text{C}_2\text{H}_3\text{O}_2^-\)) and water. This process generally involves a complete reaction.
3. **Neutralization with an Acid:** Adding an acid leads to the conversion of the acetate ion back to
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