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Table 4 Volume of Moles of Moles of moles of sodium acètate Log pK, pH Acetic Acid Acetic Sodium moles acetic acid mol Na Ac of Acid (mol) Acetate (mol) Solution HAC mol HAC Added (mL) 2.00 12.5 mol 0.001 mol 0.00008 4.74 4.00 6.25 mol 0.001 mol 0.00016 4.74 6.00 4.17 mol 0.001 mol 0.00024 4.74 8.00 3.13 mol 0.001 mol 0.00032 4.74

Table 4 Volume of Moles of Moles of moles of sodium acètate Log pK, pH Acetic Acid Acetic Sodium moles acetic acid mol Na Ac of Acid (mol) Acetate (mol) Solution HAC mol HAC Added (mL) 2.00 12.5 mol 0.001 mol 0.00008 4.74 4.00 6.25 mol 0.001 mol 0.00016 4.74 6.00 4.17 mol 0.001 mol 0.00024 4.74 8.00 3.13 mol 0.001 mol 0.00032 4.74

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I need help finding the log and pH.

**Table 3: Moles of Acetic Acid** | Volume of Acetic Acid Solution Added (mL) | Volume of Acetic Acid Solution Added (L) | Molarity of Acetic Acid Solution (M) | Moles of Acetic Acid Added (mol) | |------------------------------------------|------------------------------------------|-------------------------------------|-----------------------------------| | 2.00 | 0.002 | 0.025 M | 12.5 mol | | 4.00 | 0.004 | 0.025 M | 6.25 mol | | 6.00 | 0.006 | 0.025 M | 4.17 mol | | 8.00 | 0.008 | 0.025 M | 3.13 mol | **Table 4** | Volume of Acetic Acid Solution Added (mL) | Moles of Acetic Acid (mol) | Moles of Sodium Acetate (mol) | \(\frac{\text{moles of sodium acetate}}{\text{moles of acetic acid}}\) | \(\log\left(\frac{\text{mol NaAc}}{\text{mol HAc}}\right)\) | \(pK_a\) of HAc | pH | |-------------------------------------------|----------------------------|-------------------------------|-----------------------------------------------------------------|---------------------------------------------------------------|----------------|-----| | 2.00 | 12.5 mol | 0.001 mol | 0.00008 | | 4.74 | | 4.00 | 6.25 mol | 0.001 mol | 0.00016 | | 4.74 | | 6.00 | 4.17 mol | 0.001 mol | 0.00024 | | 4.74 | | 8.00 | 3.13 mol | 0.001 mol | 0.00032 | | 4.74 | These tables provide data for an experiment involving acetic acid and sodium acetate, likely aimed at exploring acid-base chemistry and buffer solutions. The tables offer insights into the moles of acetic acid added at different solution volumes and the corresponding pH values.
Transcribed Image Text:**Table 3: Moles of Acetic Acid** | Volume of Acetic Acid Solution Added (mL) | Volume of Acetic Acid Solution Added (L) | Molarity of Acetic Acid Solution (M) | Moles of Acetic Acid Added (mol) | |------------------------------------------|------------------------------------------|-------------------------------------|-----------------------------------| | 2.00 | 0.002 | 0.025 M | 12.5 mol | | 4.00 | 0.004 | 0.025 M | 6.25 mol | | 6.00 | 0.006 | 0.025 M | 4.17 mol | | 8.00 | 0.008 | 0.025 M | 3.13 mol | **Table 4** | Volume of Acetic Acid Solution Added (mL) | Moles of Acetic Acid (mol) | Moles of Sodium Acetate (mol) | \(\frac{\text{moles of sodium acetate}}{\text{moles of acetic acid}}\) | \(\log\left(\frac{\text{mol NaAc}}{\text{mol HAc}}\right)\) | \(pK_a\) of HAc | pH | |-------------------------------------------|----------------------------|-------------------------------|-----------------------------------------------------------------|---------------------------------------------------------------|----------------|-----| | 2.00 | 12.5 mol | 0.001 mol | 0.00008 | | 4.74 | | 4.00 | 6.25 mol | 0.001 mol | 0.00016 | | 4.74 | | 6.00 | 4.17 mol | 0.001 mol | 0.00024 | | 4.74 | | 8.00 | 3.13 mol | 0.001 mol | 0.00032 | | 4.74 | These tables provide data for an experiment involving acetic acid and sodium acetate, likely aimed at exploring acid-base chemistry and buffer solutions. The tables offer insights into the moles of acetic acid added at different solution volumes and the corresponding pH values.
Expert Solution
Step 1

Calculate the log(mol NaAc/mol HAc) value,

 

            log(mol NaAcmol HAc) = log (0.00008) = -4.1log(mol NaAcmol HAc) =  log (0.00016) = -3.8 log(mol NaAcmol HAc) = log (0.00024) = -3.6log(mol NaAcmol HAc) =  log (0.00032) = -3.5

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