Part A 0.100 M in HBr and 0.140 M in HCHO₂ (K₁ = 1.8 x 10-¹) Express your answer to two decimal places. pH Submit Part B 195| ΑΣΦ % Request Answer ESMO ? 0.165 M in HNO₂ (K₁ = 4.6 x 104) and 8.00x10-2 M in HNO3 Express your answer to two decimal places. 195) ΑΣΦ B ?
Part A 0.100 M in HBr and 0.140 M in HCHO₂ (K₁ = 1.8 x 10-¹) Express your answer to two decimal places. pH Submit Part B 195| ΑΣΦ % Request Answer ESMO ? 0.165 M in HNO₂ (K₁ = 4.6 x 104) and 8.00x10-2 M in HNO3 Express your answer to two decimal places. 195) ΑΣΦ B ?
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Solve correctly please.
All three subparts need.
![▼
Part A
0.100 M in HBr and 0.140 M in HCHO₂ (K₁ = 1.8 × 10-¹)
Express your answer to two decimal places.
pH =
Submit
Part B
pH =
Submit
0.165 M in HNO2 (Ka 4.6 x 10-4) and 8.00x10-2 M in HNO3
Express your answer to two decimal places.
Part D
15| ΑΣΦ
Request Answer
pH =
=
15. ΑΣΦ
Request Answer
SANO ?
195] ΑΣΦ
4.00×10-2 M in acetic acid (K, 1.8 x 10-5) and 4.00x10-2 M in hydrocyanic acid
(K. = 4.9 × 10-10)
Express your answer to two decimal places.
?](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F98ddc1e7-1afc-4f0e-b623-cf5e11e78fa9%2F7559e7f7-6d58-42c4-9eab-6cde587645bb%2Fj6ptln_processed.jpeg&w=3840&q=75)
Transcribed Image Text:▼
Part A
0.100 M in HBr and 0.140 M in HCHO₂ (K₁ = 1.8 × 10-¹)
Express your answer to two decimal places.
pH =
Submit
Part B
pH =
Submit
0.165 M in HNO2 (Ka 4.6 x 10-4) and 8.00x10-2 M in HNO3
Express your answer to two decimal places.
Part D
15| ΑΣΦ
Request Answer
pH =
=
15. ΑΣΦ
Request Answer
SANO ?
195] ΑΣΦ
4.00×10-2 M in acetic acid (K, 1.8 x 10-5) and 4.00x10-2 M in hydrocyanic acid
(K. = 4.9 × 10-10)
Express your answer to two decimal places.
?
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