Imaginary Axis (seconds) 1 6. Root locus for a closed-loop system with L(s) = is shown below. s(s+4)(s+6) 15 10- 0.89 0.95 0.988 0.988 -10 0.95 -15 -25 0.89 20 Root Locus 0.81 0.7 0.56 0.38 0.2 5 10 15 System: sys Gain: 239 Pole: -0.00417 +4.89 Damping: 0.000854 Overshoot (%): 99.7 Frequency (rad/s): 4.89 System: sys Gain: 16.9 Pole: -1.57 Damping: 1 Overshoot (%): 0 Frequency (rad/s): 1.57 0.81 0.7 0.56 0.38 0.2 -20 -15 -10 -5 5 10 Real Axis (seconds) From the values shown in the figure, compute the following. a) Range of K for which the closed-loop system is stable. b) Range of K for which the closed-loop step response will not have any overshoot. Note that when all poles are real, the step response has no overshoot. c) Smallest possible peak time of the system. Note that peak time is the smallest when wa is the largest for the dominant pole. d) Smallest possible settling time of the system. Note that peak time is the smallest when σ is the largest for the dominant pole.
Imaginary Axis (seconds) 1 6. Root locus for a closed-loop system with L(s) = is shown below. s(s+4)(s+6) 15 10- 0.89 0.95 0.988 0.988 -10 0.95 -15 -25 0.89 20 Root Locus 0.81 0.7 0.56 0.38 0.2 5 10 15 System: sys Gain: 239 Pole: -0.00417 +4.89 Damping: 0.000854 Overshoot (%): 99.7 Frequency (rad/s): 4.89 System: sys Gain: 16.9 Pole: -1.57 Damping: 1 Overshoot (%): 0 Frequency (rad/s): 1.57 0.81 0.7 0.56 0.38 0.2 -20 -15 -10 -5 5 10 Real Axis (seconds) From the values shown in the figure, compute the following. a) Range of K for which the closed-loop system is stable. b) Range of K for which the closed-loop step response will not have any overshoot. Note that when all poles are real, the step response has no overshoot. c) Smallest possible peak time of the system. Note that peak time is the smallest when wa is the largest for the dominant pole. d) Smallest possible settling time of the system. Note that peak time is the smallest when σ is the largest for the dominant pole.
Power System Analysis and Design (MindTap Course List)
6th Edition
ISBN:9781305632134
Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Chapter6: Power Flows
Section: Chapter Questions
Problem 6.10MCQ
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Transcribed Image Text:Imaginary Axis (seconds)
1
6. Root locus for a closed-loop system with L(s) =
is shown below.
s(s+4)(s+6)
15
10-
0.89
0.95
0.988
0.988
-10
0.95
-15
-25
0.89
20
Root Locus
0.81
0.7
0.56
0.38
0.2
5
10
15
System: sys
Gain: 239
Pole: -0.00417 +4.89
Damping: 0.000854
Overshoot (%): 99.7
Frequency (rad/s): 4.89
System: sys
Gain: 16.9
Pole: -1.57
Damping: 1
Overshoot (%): 0
Frequency (rad/s): 1.57
0.81
0.7
0.56
0.38
0.2
-20
-15
-10
-5
5
10
Real Axis (seconds)
From the values shown in the figure, compute the following.
a) Range of K for which the closed-loop system is stable.
b) Range of K for which the closed-loop step response will not have any overshoot.
Note that when all poles are real, the step response has no overshoot.
c) Smallest possible peak time of the system. Note that peak time is the smallest
when wa is the largest for the dominant pole.
d) Smallest possible settling time of the system. Note that peak time is the smallest
when σ is the largest for the dominant pole.
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