if the p-value is 0.027 then what is your conclusion concerning the null hypothesis?
Q: Fran is training for her first marathon, and she wants to know if there is a significant difference…
A: The objective of this question is to test the claim that there is a significant difference between…
Q: Suppose I surveyed a random sample of commuters who had jobs in Manhattan, 51 whose primary mode of…
A: Given information: n1=51M1=40,000s1=5100n2=80M2=60,000s2=8000 a) the difference of the sample means:…
Q: A college student is interested in investigating the claim that students who graduate with a…
A: The given data is as follows:Recent graduates with a master's degreeSample size, Sample mean,…
Q: Fran is training for her first marathon, and she wants to know if there is a significant difference…
A: Let be the group runners training for marathons be population 1 and be the individual runners…
Q: A pharmaceutical company needs to know if its new cholesterol drug, Praxor, is effective at lowering…
A: Let the treatment group be population 1 let the control group be population 2significance…
Q: A marketing consultant is hired by a major restaurant chain wishing to investigate the preferences…
A: The P-Value is .076574.The result is significant at p < 0.10.
Q: Fran is training for her first marathon, and she wants to know if there is a significant difference…
A: Sample mean (x̅1) = 42.8Sample mean (x̅2) = 40.9Sample size (n1) = 34Sample size (n2) = 41Standard…
Q: Fran is training for her first marathon, and she wants to know if there is a significant difference…
A: The objective of this question is to test the claim that there is a significant difference between…
Q: Dr. Vegapunk thinks that watching anime (Japanese animated shows) decreases social skills in college…
A:
Q: An auditor, pressed for time and on a low budget, is concerned with account errors on customer…
A: The null and alternative hypotheses are;
Q: Fran is training for her first marathon, and she wants to know if there is a significant difference…
A: Solution
Q: To interpret his finding, he needs to calculate the probability that a sample of 25 graduates would…
A: Let X is the random variable of the salary of the school’s graduates one year after graduation.…
Q: An article presents a study of health outcomes in women with symptoms of heart disease. In a sample…
A:
Q: 3. At a community college, evening classes tend to have more reentry students than day classes,…
A: Given : Claim : The mean age of day students is less than the mean age of evening students.
Q: Insurance Company A claims that its customers pay less for car insurance, on average, than customers…
A: Company A Sample size, n1=11 Sample mean, x¯1=150 Sample sd, s1=12 Company B Sample size, n2=13…
Q: Suppose the Board of Trustees of a wealthy private university has decided that it wants to waive…
A: Normal random variable x follows the distribution with bell shaped curve. The normal distribution is…
Q: Dr. Vegapunk thinks that watching anime (Japanese animated shows) decreases social skills in college…
A: Dr. Vegapunk thinks that watching anime (Japanese animated shows) decreases social skills in college…
Q: According to a new study by ABC, the average time spent by young adults ages 20 to 25 in using their…
A: Given information Level of significance=0.10, n=sample size=30, sample mean x̄=7.8, s=sample…
Q: A pharmaceutical company needs to know if its new cholesterol drug, Praxor, is effective at lowering…
A: The objective of this question is to test the pharmaceutical company's claim that its new…
Q: According to a new study by ABC, the average time spent by young adults ages 20 to 25 in using their…
A: Given that
Q: According to data from the 2010 United States Census, 64.2% of Americans in Susanville, CA were…
A: 64.2% of Americans in Susanville, CA were male, p = 0.642 Sample size, n = 100 Among the sample, 54…
Q: Suppose I surveyed a random sample of commuters who had jobs in Manhattan, 51 whose primary mode of…
A: Given that We have to find (a) The question of interest is whether the mean…
Q: he U.S. Department of Labor collects data on unemployment insurance payments made to unemployed…
A:
Q: Suppose that Randy is an analyst for the bicyling industry and wants to estimate the asking price of…
A: Given information- Sample size, n = 10 Sample mean, x-bar = $659.87 Sample standard deviation, s =…
Q: Fran is training for her first marathon, and she wants to know if there is a significant difference…
A: Given data,n1=40x1=46.6σ1=4.6n2=45x2=48.8σ2=2.4Compute value of test statistic?
Q: A government agency provides the number of miles that residents of the 75 largest metropolitan areas…
A: (a) Obtain the point estimate of the difference between the mean number of miles that City A…
Q: Insurance Company A claims that its customers pay less for car insurance, on average, than customers…
A: From the provided information,
Q: Fran is training for her first marathon, and she wants to know if there is a significant difference…
A: Let be the group runners training for marathons be population 1 and be the individual…
Q: A pharmaceutical company needs to know if its new cholesterol drug, Praxor, is effective at lowering…
A: a)To testH0:μ1=μ2H1:μ1<μ2 It is given that n1=39x1=19.8s1=2.1n2=46x2=18.4s2=2.8
Q: In a study investigating the effect of car speed on accident severity, 5,000 reports of fatal…
A: given dataN = 5000normal distributionμ = 45 mphσ = 14 mph
Q: A marketing research company wants to determine if there is a difference in the mean satisfaction…
A: Given information n1=n2=100, sample mean x̄1=4.6, sample mean x̄2=4.5, standard deviation s1=s2=0.8…
Q: In a random sample of 6 cell phones, the mean full retail price was $541.20 and the standard…
A: The given data is as follows:Sample size, Sample mean, Sample standard deviation, Population mean,
Q: a. The range of the data is b. The standard deviation of the data is (Round your answer to 2 decimal…
A: a.A data set is given.The number of observations is n = 16.
Q: Suppose I surveyed a random sample of commuters who had jobs in Manhattan, 51 whose primary mode of…
A: Confidence interval are used to estimate the interval where the true popualtion parameter can…
Q: The following table contains the number of successes and failures for three categories of a variable…
A: The given data is as follows: Category 1Category 2Category 3Failures493343Successes763848
Q: A report states that the mean yearly salary offer for students graduating with a degree in…
A: From the provided information, Sample size (n) = 50 Sample mean (x̅) = 49830 Sample standard…
Q: A pharmaceutical company needs to know if its new cholesterol drug, Praxor, is effective at lowering…
A: Given Data : For treatment group x̄1 = 23.2 s1 = 4.4 n1 = 38 For…
Q: K.Brew sells a wide variety of outdoor equipment and clothing. The company sells both through mail…
A: Given:n1 = 18 = 81.30s1 = 16.25n2 = 9 = 67s2 = 15.25Formula Used:
Q: The effectiveness of a blood-pressure drug is being investigated. An experimenter finds that, on…
A: We have given that, Sample mean (x̄) = 60.9, standard deviation (s)= 16.9 and sample size (n) = 21…
Q: The average McDonald's restaurant generates $3.6 million in sales each year with a standard…
A: In this question given that survey of 27 restaurant Find out a null and alternative hypothesis…
Q: Test the claim at the 0.05 level of significance. Let recent graduates with a master's degree be…
A:
Step by step
Solved in 2 steps
- Fran is training for her first marathon, and she wants to know if there is a significant difference between the mean number of miles run each week by group runners and individual runners who are training for marathons. She interviews 37 randomly selected people who train in groups, and finds that they run a mean of 47.7 miles per week. Assume that the population standard deviation for group runners is known to be 3.3 miles per week. She also interviews a random sample of 49 people who train on their own and finds that they run a mean of 49.4 miles per week. Assume that the population standard deviation for people who run by themselves is 4.4 miles per week. Test the claim at the 0.10 level of significance. Let group runners training for marathons be Population 1 and let individual runners training for marathons be Population 2. Step 2 of 3 : Compute the value of the test statistic. Round your answer to two decimal places.1) A study compared the weight loss of people on a low-fat diet versus people on a low-carb diet. In a sample of 100 obese people on a low-fat diet the sample mean weight loss as 7.6 pounds with a standard deviation of 3.2 pounds. In another sample of 120 obese people on a low-carb diet the sample mean weight loss was 6.7 pounds with a standard deviation of 3.9 pounds. a) Test the hypothesis, at the 5% level of significance, that there is a difference in the mean weight loss of using the 2 different diets. b) What is the p-value?A cell phone company offers contract phones and non-contract phones. In a sample of 40 contract subscribers, the mean yearly income was found to be $57,000 with a standard deviation of $9,200. In a sample of 30 non-contract phones, the mean yearly income was found to be $53,000 with a standard deviation of $7,100. At the 1% significance level, is there evidence that the mean annual income level between the two groups is the same? Include a p-value with your test.
- Because of different sales ability, experience, and devotion, the incomes of real estate agents vary considerably. Suppose that in a large city the annual income is normally distributed with a standard deviation of $15,000. A real estate industry expert claims that the mean annual income of all real estate agent in the city is equal to $79000. A sample of 30 real estate showed that their mean annual income was $84230. Test the manager's claim using a level of significance of 0.05. what is your conclusionA pharmaceutical company needs to know if its new cholesterol drug, Praxor, is effective at lowering cholesterol levels. It believes that people who take Praxor will average a greater decrease in cholesterol level than people taking a placebo. After the experiment is complete, the researchers find that the 44 participants in the treatment group lowered their cholesterol levels by a mean of 18.7 points with a standard deviation of 3.3 points. The 39 participants in the control group lowered their cholesterol levels by a mean of 18.1 points with a standard deviation of 2.1 points. Assume that the population variances are not equal and test the company’s claim at the 0.02 level. Let the treatment group be Population 1 and let the control group be Population 2. Step 1 of 3 : State the null and alternative hypotheses for the test. Fill in the blank below. H0: μ1=μ2 Ha : μ1⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯μ2 Step 2 of 3: what is the test statistic Step 3 of 3: draw a conclusion, fail or reject. Is…Insurance Company A claims that its customers pay less for car insurance, on average, than customers of its competitor, Company B. You wonder if this is true, so you decide to compare the average monthly costs of similar insurance policies from the two companies. For a random sample of 12people who buy insurance from Company A, the mean cost is $153 per month with a standard deviation of $16. For 15 randomly selected customers of Company B, you find that they pay a mean of $160 per month with a standard deviation of $10. Assume that both populations are approximately normal and that the population variances are equal to test Company A’s claim at the 0.10 level of significance. Let customers of Company A be Population 1 and let customers of Company B be Population 2. Step 1 of 3: State the null and alternative hypotheses for the test. Fill in the blank below. H0: μ1=μ2 Ha: μ1_____μ2 Step 2 of 3: Compute the value of the test statistic. Round your answer to three decimal places Step 3 of…
- Barron's has collected data on the top 1,000 financial advisers. Company A and Company B have many of their advisers on this list. A sample of 16 of the Company A advisers and 10 of the Company B advisers showed that the advisers managed many very large accounts with a large variance in the total amount of funds managed. The standard deviation of the amount managed by the Company A advisers was s1 = $583 million. The standard deviation of the amount managed by the Company B advisers was s2 = $488 million. Conduct a hypothesis test at ? = 0.10 to determine if there is a significant difference in the population variances for the amounts managed by the two companies. What is your conclusion about the variability in the amount of funds managed by advisers from the two firms? State the null and alternative hypotheses. H0: ?12 ≠ ?22 Ha: ?12 = ?22 H0: ?12 ≤ ?22 Ha: ?12 > ?22 H0: ?12 = ?22 Ha: ?12 ≠ ?22 H0: ?12 > ?22 Ha: ?12 ≤ ?22 Find the value of the test statistic.…A pharmaceutical company needs to know if its new cholesterol drug, Praxor, is effective at lowering cholesterol levels. It believes that people who take Praxor will average a greater decrease in cholesterol level than people taking a placebo. After the experiment is complete, the researchers find that the 46 participants in the treatment group lowered their cholesterol levels by a mean of 19.5 points with a standard deviation of 4.9 points. The 37 participants in the control group lowered their cholesterol levels by a mean of 18.4 points with a standard deviation of 4.1 points. Assume that the population variances are not equal and test the company's claim at the 0.02 level. Let the treatment group be Population 1 and let the control group be Population 2. Step 2 of 3: Compute the value of the test statistic. Round your answer to three decimal places.According to Kaiser Family Foundation survey in 2011 and 2010, the average premium for employer-sponsored health insurance for family coverage was $15,073 in 2011 and $13,770 in 2010 (USA TODAY, September 29, 2011). Suppose that these averages were based on random samples of 250 and 200 employees who had such employer-sponsored health insurance plans for 2011 and 2010, respectively. Further assume that the population standard deviations for 2011 and 2010 were $2160 and $1990, respectively.
- 10According to the Insurance Association in US, the average annual expenditure for automobile insurance is $605. Suppose that in a simple random sample of 80 residents of New York, for most recent year their average expenditure was $638.62 with the standard deviation of $106.05. Based on these data, examine whether the average annual insurance for motorists in New York might be different from that in national level. Using the 0.05 level of significance, what conclusion do you reach? Also, construct and interpret 95% confidence interval for the population mean. Is the hypothesized mean within the interval? Is this consistent with the findings of the hypothesis test conducted?A pharmaceutical company needs to know if its new cholesterol drug, Praxor, is effective at lowering cholesterol levels. It believes that people who take Praxor will average a greater decrease in cholesterol level than people taking a placebo. After the experiment is complete, the researchers find that the 34 participants in the treatment group lowered their cholesterol levels by a mean of 22.2 points with a standard deviation of 3.4 points. The 42 participants in the control group lowered their cholesterol levels by a mean of 21.2 points with a standard deviation of 1.8 points. Assume that the population variances are not equal and test the company's claim at the 0.10 level. Let the treatment group be Population 1 and let the control group be Population 2. Step 1 of 3: State the null and alternative hypotheses for the test. Fill in the blank below. Ho:₁ = ₂ Ha: M •M₂
